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3 years ago

Which equation shows this relationship? 8 less a number (n) is 21.

Mathematics

1 answer:

GarryVolchara [31]3 years ago

8 0

N-8=21 should be the answer

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Help me for brainliest. Non serious answers will be reported

OLEGan [10]

Answer:

Step-by-step explanation:

25*20*4=2000

40*10=400

2000-400=1600

4 0

3 years ago

Estimate 51710-36736 by first rounding each number to the nearest thousand.

lawyer [7]

Answer:

15,000

Step-by-step explanation:

51,710 to the nearest thousand is 52,000. 36,736 to the nearest thousand is 37,000.

51,000-37,000=15,000

5 0

3 years ago

$300 was deposited in a Certificate of Deposit (CD) yielding 6% interest compounded quarterly. how many years will it take the C

Ivan

The future value (A) of a one-time investment of principal amount P at interest rate r compounded n times per year for t years is ...

... A = P(1 +r/n)^(nt)

Putting your given numbers into the formula, we have

... 876.34 = 300(1 +.06/4)^(4t)

Taking logarithms, this becomes the linear equation

... log(876.34) = log(300) + 4t·log(1.015)

Solving for t in the usual way, we get

... log(876.34) -log(300) = 4t·log(1.015) . . . . . . . subtract the constant term on the right

... (log(876.34) -log(300))/(4·log(1.015)) = t ≈ 18.00 . . . . divide by the coefficient of t

It will take <em>18 years</em> for the $300 CD to reach a value of $876.34.

8 0

3 years ago

How do you find the volume of the solid generated by revolving the region bounded by the graphs

d1i1m1o1n [39]

Answer:

About the x axis

$V = 4\pi[ \frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

Step-by-step explanation:

For this case we have the following functions:

$y = 2x^2 , y=0, X=2$

About the x axis

Our zone of interest is on the figure attached, we see that the limit son x are from 0 to 2 and on y from 0 to 8.

We can find the area like this:

$A = \pi r^2 = \pi (2x^2)^2 = 4 \pi x^4$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= 4\pi \int_{0}^2 x^4 dx$

$V = 4\pi [\frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

For this case we need to find the function in terms of x like this:

$x^2 = \frac{y}{2}$

$x = \pm \sqrt{\frac{y}{2}}$ but on this case we are just interested on the + part $x=\sqrt{\frac{y}{2}}$ as we can see on the second figure attached.

We can find the area like this:

$A = \pi r^2 = \pi (2-\sqrt{\frac{y}{2}})^2 = \pi (4 -2y +\frac{y^2}{4})$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \pi \int_{0}^8 2-2y +\frac{y^2}{4} dy$

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

The figure 3 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (8-2x^2)^2 = \pi (64 -32x^2 +4x^4)$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= \pi \int_{0}^2 64-32x^2 +4x^4 dx$

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

The figure 4 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (\sqrt{\frac{y}{2}})^2 = \pi\frac{y}{2}$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \frac{\pi}{2} \int_{0}^8 y dy$

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

6 0

3 years ago

Kevin using 84 fluid ounces of water to make in all purpose cleaner. The directions call for 4 fluid ounces of concentrated soap

nata0808 [166]

He should use 886 fluid ounces of soap.

<u>Step-by-step explanation</u>:

Know that 8 fluid ounces make 1 cup.

Now 24 cups need 32 fluid ounces or, 3 fluid ounces of water need 32 fluid ounces of soap.

Thus, by unitary method,

84 ounces of water need 32 × 84 / 3 ounces of soap.

Thus the answer comes to 886 ounces.

7 0

3 years ago