Relative extrema occur where the derivative is zero (at least for your polynomial function).
So taking the derivative we get
<span>20<span>x3</span>−3<span>x2</span>+6=0
</span><span>
This is a 3rd degree equation, now if we are working with complex numbers this equation is guaranteed to have 3 solutions by the fundamental theorem of algebra. But the number of real roots are 1 which can be found out by using Descartes' rule of signs. So the maximum number of relative extrema are 1.</span>
I think they should keep it around, even if it might not be the most efficient strategy. After all, what if you need to solve a problem using multiple strategies?
9x = 27
x = 3
y = -1
The answer is (3, -1)
Answer:
<u>The correct answer is D. x + 5≤ - 4</u>
Step-by-step explanation:
Let's review which inequality has - 12 in its solution set, this way:
A. x + 6 less-than negative 8
-12 + 6 < - 8
-6 < - 8 Not correct
B. x + 4 greater-than-or-equal-to negative 6
- 12 + 4 ≥ - 6
- 8 ≥ - 6 Not correct
C. x minus 3 greater-than negative 10
- 12 - 3 > - 10
<u>- 15 > - 10 Not correct</u>
D. x + 5 less-than-or-equal-to negative 4
- 12 + 5 ≤ - 4
- 7 ≤ - 4 This is correct
<u>The correct answer is D. x + 5≤ - 4</u>