When they give you a x intercept and y intercept how do you write the equation

Will mark brainliest if answered correctly!

Dima020 [189]

<h3>Answer: </h3>

about 1.768 seconds

<h3>Explanation:</h3>

Since the phone is <em>dropped</em>, the first equation applies. The final height is assumed to be zero, so we have ...

... h(t) = 0 = -16t² +50

... 16t² = 50 . . . . . . . . add 16t²

... t² = 50/16 . . . . . . . . divide by 16

... t = √3.125 . . . . . . . take the square root

... t ≈ 1.768 . . . . . . . . round to milliseconds

5 0

3 years ago

I would appreciate it a lot

Volgvan

Answer:

C

Step-by-step explanation:

f(x) = Price

2.00 = Price of one ride

x = number of times ridden

f(x) = 2x

3 0

3 years ago

Read 2 more answers

Find the value of x! this is geometry

saveliy_v [14]

Answer:

it's v-33

Step-by-step explanation:

I just used cymath recommended

8 0

2 years ago

(50 points!)

Maru [420]

(y x .12) x .3 = the total cost

6 0

3 years ago

A company is producing two types of ski goggles. Thirty percent of the production is of type A, and the rest is of type B. Five

exis [7]

Answer:

$\dfrac{14}{29}$

Step-by-step explanation:

Let <em>P(A) </em>be the probability that goggle of type A is manufactured

<em>P(B) </em>be the probability that goggle of type B is manufactured

<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.

According to the question,

<em>P(A)</em> = 30%

<em>P(B)</em> = 70%

<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.

P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.

$P(A \cap E)$ will be the probability that a goggle is of type A and is returned within 10 days of its purchase.

$P(B \cap E)$ will be the probability that a goggle is of type B and is returned within 10 days of its purchase.

$P(E \cap A) = P(A) \times P(E/A)$

$P(E \cap A) = \dfrac{30}{100} \times \dfrac{5}{100}\\\Rightarrow P(E \cap A) = 1.5 \%$

$P(E \cap B) = P(B) \times P(E/B)$

$P(E \cap B) = \dfrac{70}{100} \times \dfrac{2}{100}\\\Rightarrow P(E \cap B) = 1.4 \%$

$P(E) = 1.5 \% + 1.4 \% \\P(E) = 2.9\%$

If a goggle is returned within 10 days of its purchase, probability that it was of type B:

$P(B/E) = \dfrac{P(E \cap B)}{P(E)}$

$\Rightarrow \dfrac{1.4 \%}{2.9\%}\\\Rightarrow \dfrac{14}{29}$

So, the required probability is $\dfrac{14}{29}.$

7 0

3 years ago