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siniylev [52]
4 years ago
6

The gravitational force acting on an object is also called the object's _____. A) mass B) weight C) density D) volume​

Chemistry
2 answers:
Veseljchak [2.6K]4 years ago
5 0

Answer:

B) weight

Thats it no explanation

maxonik [38]4 years ago
4 0

Answer:

B) weight

Explanation:

Weight is gravity's pull on an object. This would change if you went to the moon. Gravitational

Mass is the amount of the object. This would stay the same if you went to the moon. Non-gravitational

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SO2 (0.522 mol.L-1) and O2 (0.633 mol.L-1) react and reach equilibrium. Calculate the equilibrium concentrations of the products
Amiraneli [1.4K]

Answer: Hence, the equilibrium concentration of the SO_2,O_2\text{ and }SO_3 are 0.521, 0.632 and 10.88\times 10^{-6}Mrespectively.

Explanation:

The balanced chemical reaction is:

                  SO_2(g)+2O_2(g)\rightleftharpoons 2SO_3(g)

At t = 0          0.522           0.633               0  

At t=t_{eq}      0.522-x         0.633-2x      2x

The expression for K_c for the given reaction follows:

K_c=\frac{[SO_2]^2}{[SO_2]\times [O_2]}

We are given:

K_c=5.66\times 10^{-10}

Putting values in above equation, we get:

5.66\times 10^{-10}=\frac{(2x)^2}{(0.522-x)\times (0.633-2x)^2}

x=5.44\times 10^{-6}M

Thus equilibrium concentration of SO_2 is = (0.522-x )= (0.522-5.44\times 10^{-6})=0.521

equilibrium concentration of O_2 is = (0.633-2x )= (0.633-2\times 5.44\times 10^{-6})=0.632

equilibrium concentration of SO_3 is = (2x )= (2\times 5.44\times 10^{-6})=10.88\times 10^{-6}M

8 0
4 years ago
When copper is combined with another element, ______, it makes bronze, the first man made metal alloy.
Alex Ar [27]

Answer:

tin

Explanation:

When copper is combined with another element, tin, it makes bronze, the first man made metal alloy

8 0
3 years ago
Consider an equilibrium (K1) that is established after 10 mL of compound A and 10 mL of compound B are mixed. Now, imagine the e
WARRIOR [948]

The equilibrium constant K₁ = Equilbrium constant K₂.

The equilibrium constant, K, of a reaction, is defined as:

"The ratio between concentration of products powered to their reaction quotient and concentration of reactants powered to thier reaction quotient".

For the reaction:

aA + bB ⇄ cC + dD

The equilibrium constant, K, is:

K = \frac{[C]^c[D]^d}{[A]^a[B]^b}

Now, assuming the reaction of the problem is 1:1:

A + B ⇄ C + D

K = \frac{[C][D]}{[A][B]}

The concentrations of the reactants are directly proportional to the volume added. Thus, we can assume that concentration = Volume. Replacing for K₁ and K₂:

K_1 = \frac{[C][D]}{[10mL][10mL]} = K_1 = \frac{[C][D]}{100mL^2}

In the same way:

K_2 = \frac{[C][D]}{[1mL][100mL]} = K_2 = \frac{[C][D]}{100mL^2}

Thus, we can say:

<h3>K₁ = K₂</h3><h3 />

Learn more about chemical equilibrium in:

brainly.com/question/4289021?referrer=searchResults

8 0
3 years ago
Thulium-167 has a half-life of 9.25 days. If you begin with 48 grams of thulium-167, how much of the original isotope will remai
fgiga [73]

Answer:

2.3125g

Explanation:

Half-life referred to the time required for a quantity to reduce to half of its initial value, It used to calculate how unstable atoms undergo, or the period of time and atom can survive, radioactive decay.

Given:

t(1/2)= 9.25days

Initial mass of Thulium-167 = 48grams

We need to calculate the remaining amount after 37days.

Since we know that 1 half life = 9.25 days

Then 37 days means ( 37/9.25) half lives

37days means 4 half life

That means the 38grams of Thulium-167 will be halved by 4 times.

Then the ratio between the initial Amount and the amount remaining after 37 days can be calculated as. 0.5^(4)

= 37days × 0.5^(4)

= 2.3125g

the remaining amount of Thallium-167 after 37days is 2.3125g

4 0
3 years ago
On average, one chlorine atom can destroy 100,000 ozone molecules. Such destructive power is tremendous when it is related to th
Georgia [21]
There would be no more because everything had decrease to 0
7 0
3 years ago
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