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Serggg [28]
3 years ago
11

If hydrogen is the lightest element, why don't we use it to inflate balloons

Chemistry
2 answers:
d1i1m1o1n [39]3 years ago
5 0
The element is very flammable. 
Lubov Fominskaja [6]3 years ago
3 0
Its unstable and flammable... the Hindenberg used it... we saw how that went
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The equilibrium constant, Kp, for the following reaction is 9.52×10-2 at 350 K: CH4(g) + CCl4(g) 2CH2Cl2(g) Calculate the equili
dimaraw [331]

Answer:

pCH4 =  0.9184 atm

pCCl4 = 0.9184 atm

pCH2Cl2 = 0.2832 atm

Explanation:

Step 1: Data given

The equilibrium constant, Kp= 9.52 * 10^-2

Temperature = 350 K

Each have an initial pressure of 1.06 atm

Step 2: The balanced equation

CH4(g) + CCl4(g) ⇆ 2CH2Cl2(g)

Step 3: The pressure at the equilibrium

pCH4 = 1.06 - X atm

pCCl4 = 1.06 - X atm

pCH2Cl2 = 2X

Step 4: Calculate Kp

Kp = (2X)² / (1.06 - X)*(1.06 - X)

9.52 * 10^-2 = 4X² / (1.06 - X)*(1.06 - X)

X = 0.1416

Step 5: Calculate the partial pressure

pCH4 = 1.06 - 0.1416 =  0.9184 atm

pCCl4 = 1.06 - 0.1416 =  0.9184 atm

pCH2Cl2 = 2 * 0.1416 = 0.2832 atm

Kp = (0.2832²) / (0.9184*0.9184)

Kp = 9.52 * 10^-2

pCH4 =  0.9184 atm

pCCl4 = 0.9184 atm

pCH2Cl2 = 0.2832 atm

3 0
3 years ago
Consider the given acid ionization constants. identify the strongest conjugate base. acid ka hf(aq) 3.5×10−4 hc7h5o2(aq) 6.5×10−
vfiekz [6]

higher Ka value= stronger acid

stronger acids have weaker conjugate bases, so the acid with the strongest conjugate base would be acetic acid

8 0
4 years ago
HELP PLEASE!
Lostsunrise [7]

If it is already balanced because the compounds aluminum(Al) and oxygen(O) have the same number of atoms

5 0
3 years ago
Can someone please help with chemistry? Lead has a density of 10.5 g/cm^3. What is the diameter of a lead ball that has a mass o
adelina 88 [10]
Density = Mass / Volume

10.5 = 500 / x

10.5x = 500

x = 50 cm^3 (1 sig fig) volume of the sphere

Volume of a sphere = 4/3 pi r^2

pi = 3.14 r = radius

50 = 4/3 pi r^3

50•3/4 = pi r^3

37.5 = pi r^3

37.5/pi = r^3

11.9 = r^3

cube root(11.9) = r

2.3 = r

Diameter = 2•radius

Diameter = 2 • 2.3

Diameter = 5 cm (1 sig fig) diameter



3 0
3 years ago
Which of the following reagents convert(s) benzoyl chloride to phenyl propyl ketone?a. CH3CH2CH2MgBrb. CH3CH2CH2Lic. (CH3CH2CH2)
Gelneren [198K]

Answer:C

(CH3CH2CH2)2CuLi

Explanation:

The reaction between acyl halides and Grignard reagents or acyl halides and organolithium compounds does not form ketones because the reagents ( Grignard reagent and organo lithium compounds) are too reactive hence the ketone intermediate reacts further to form tertiary alcohols hence the ketone cannot be isolated.

3 0
3 years ago
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