What is the distance between points (-5, 5) and (2, 3)
1 answer:
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Answer:
129.3 in²
Step-by-step explanation:
The shaded segment is calculated as
area of sector ABC - area of triangle ABC
area of sector = area of circle × fraction of circle
A = πr² ×
= π × 18² ×
= 324π × = 54π in²
area of Δ ABC = × 18 × 18 × sin60° ≈ 40.30 in²
Then
shaded area = 54π - 40.30 ≈ 129.3 in² ( to the nearest tenth )