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Juli2301 [7.4K]
3 years ago
15

This week laptops are 25% off. If a laptop costs $340, what is its sale price?

Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

____________________________________________________

Answer:

Your answer would be $255

____________________________________________________

Step-by-step explanation:

To solve these kind of problems, what we have to do is find how much of 340 is 25%, and then subtract that number to the original price.

Let's give you some important information in the text:

  • 25% off
  • $340

With the information above, we can solve our problem.

First, we would need to find how much of 340 is 25%, and to do that, we would multiply 340 by 0.25:

340*0.25 = 85

When you solve, you should get 85. But, you're not done yet, we need to find out how much the sales price is, not how much of it is discounted.

In order to find the sales price, we would get our original number (the number it originally cost), and subtract it with the amount of money it's removing (85).

In this case, we would subtract 340 by 85.

340-85=255

Your FINAL answer should be 255

The sales price of the laptop would be $255.

____________________________________________________

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Damm [24]

Answer:

So, to 1 d.p. 7 is about 23% out of 30. (7 of 30=23%)

Step-by-step explanation:

7/30 x 100 =23.3333333333% or 70/3%.

6 0
2 years ago
E
AlexFokin [52]

For this case we have that by definition, the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

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According to the statement data we have:

m = 5\\(x_ {0}, y_ {0}): (- 8,1)

Substituting we have:

y-1 = 5 (x - (- 8))

By law of signs of multiplication we have to:

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Answer:

The requested equation is: y-1 = 5 (x + 8)

5 0
3 years ago
Aya = a1 + (n - 1)d
Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

Step-by-step explanation:

Given

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  • d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

substituting a₁ = -33 and d = 4 in the nth term of the sequence

a_n=-33+\left(n-1\right)4

\:a_n=-33+4n-4

a_n=4n-37

Thus, the nth term of the sequence is:

a_n=4n-37

now substituting n = 26 in the nth term to determine the 26th term of the sequence

a_n=4n-37

a_{26}=4\left(26\right)-37

a_{26}=104-37

a_{26}=67

Therefore, the 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

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2 years ago
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