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3 years ago

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Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

8 0

Given two points

$(x_1,y_1),\quad (x_2,y_2)$

The slope of the line passing through both is

$m=\dfrac{\Delta y}{\Delta x}=\dfrac{y_2-y_1}{x_2-x_1}$

Plugging your values, we have

$m=\dfrac{7-3}{8-1}=\dfrac{4}{7}$

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If the seed company recommends planting approximately 350 grass seeds per square meter, about how many grass seeds will he need?

Svetach [21]

Answer:

83422.5 grass seeds

Step-by-step explanation:

Applying,

A = 1/2bh....................... Equation 1

Where A = Area of the Triangle, b = base, h = height.

But, from the diagram,

tanФ = 20/b

b = 20/tanФ.................. Equation 2

Substitute equation 2 into equation 1

A = 1/2(20/tanФ)(h)................ Equation 3

Given: h = 20 m, Ф = 40°

Substitute these values into equation 3

A = 1/2(20×20)/tan40°

A = 200/tan40°

A = 238.35 m²

If the seed company recommends planting approximately 350 grass seeds per square meter,

Therefore,

Number of grass seed need = (350×238.35)

Number of grass seed needed = 83422.5 grass seeds

3 0

3 years ago

Write the sentence as an equation.<br> 102 is the same as the product of 189 and p, decreased by 80

rosijanka [135]

Answer:

102+189p-80

Step-by-step explanation:

8 0

2 years ago

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

Help picture attached

Vilka [71]

I would say c or d. but since its multiple choice, its ok to guess sometimes.

6 0

3 years ago

A coin is fixed so that the probability to get heads in two throws is double the probability. Count the probability that there w

Setler [38]

Answer:

no clue try looking it up on here see what you find

Step-by-step explanation:

i just wanna help but im not very smart

5 0

3 years ago