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Alika [10]
3 years ago
6

The drop-counter is misaligned with the buret, causing it to miss counting every one out of five drops of base added to the HCl.

This error means the calculated molarity of the HCl solution will be ___________ its actual concentration.
Chemistry
1 answer:
Airida [17]3 years ago
4 0

Answer:

Less than

Explanation:

According to the question, the drop counter is counting four out of five drops of base added to the HCl. So when the titration will reach to the end point the volume of Base recorded will be less than the actual volume of the base dropped in the solution.

We will use law of equivalence for the calculation of concentration of HCl,

M_1V_1 = M_2V_2

Where, M_1 and V_1 are molarity and volume of HCl and M_2 and V_2 are molarity of volume of the base added.

Thus concentration of HCl will be calculated as,

M_1=\frac{M_2V_2}{V_1}

As the recorded V_2 is less than the actual amount present in the solution, the calculated value of concentration of HCl will also be less than the actual.

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Which type of van der walls force is responsible for holding polar molecules together? london dispersion dipole-dipole hydrogen
svet-max [94.6K]

Answer:

dipole-dipole

Explanation:

Polar molecules are formed as result of covalent bonds between atoms.

Dipole-dipole attraction are intermolecular bonds. Both London dispersion forces and dipole-dipole attraction are van der waals forces.

In dipole-dipole attraction, polar molecules (unsymmetrical molecules) line up such that the positive pole of one molecule attracts the negative pole of another. Example of such is found in HCl.

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3 years ago
When hydrochloric acid is poured over potassium sulfide, 43.7 mLmL of hydrogen sulfide gas is produced at a pressure of 758 torr
kvasek [131]

Answer:

0.196 grams of K2S reacted

Explanation:

When hydrochloric acid is poured over potassium sulfide, 43.7 mLmL of hydrogen sulfide gas is produced at a pressure of 758 torrtorr and 26.0 ∘C

How much potassium sulfide has reacted in grams?

Step 1: Data given

Volume of hydrogen sulfide (H2S) produced = 43.7 mL

Pressure = 758 torr = 758/760 = 0.9973684 atm

Temperature = 26.0 °C = 273 + 26 = 299 K

Step 2: The balanced equation

2 HCl + K2S → H2S + 2 KCl

Step 3: Calculate moles H2S

p*V = nRT

n = (pV)/(RT)

⇒ with n= the number of moles of H2S

⇒ with p = the pressure = 0.9973684 atm

⇒ with V = the volume of the gas = 43.7 mL = 0.0437 L

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = The temperature = 26°C = 299 Kelvin

n = (0.9973684 * 0.0437)/ (0.08206*299)

n = 0.001776 moles H2S

Step 4: calculate moles of K2S

For  2 moles HCl we need 1 mol K2S to produce 1 mol H2S and 2 moles KCl

For 0.001776 moles H2S produced, we need 0.001776 moles K2S

Step 5: Calculate mass of K2S

Mass K2S = moles K2S * molar mass K2S

Mass K2S = 0.001776 moles * 110.26 g/mol

Mass K2S = 0.196 grams K2S

0.196 grams of K2S reacted

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