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zmey [24]
3 years ago
5

80 POINTS + BRAINLIEST !!!!!!!!

Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0

Solution:

we are given that

Clayton needs to reflect the triangle below across the line y=x.

And as we know the reflection of the point (x,y) across  the line y = x is the point (y, x).

Hence the new Traingle will be on the other side of the line y=x and position of x and y-coordinates of the vertices of the trangle gets interchanged.

Hence the Options that applies are:

C’ will move because all points move in a reflection.

The image and the pre-image will be congruent triangles. (Because reflection just changes the position of the trinagle not the property)

The image and pre-image will not have the same orientation because reflections flip figures.

GaryK [48]3 years ago
5 0

Point C’ will move because all points move in a reflection.  The image and the pre-image will be congruent triangles

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Please help! <3
igomit [66]

Answer:

8 square units

Step-by-step explanation:

Area of a rectangle= lenght x width

locating the four points on a Cartesian plane

lenght = BC= AD = (0,4)->(4,4) = 4units

width = AB = CD = (0,2)-> (0,4) = 2units

Area of rectangle = 4units x 2units = 8 square units

3 0
3 years ago
Which is the equation of the line shown in the graph?
elixir [45]

I think the right answer is A

6 0
3 years ago
Read 2 more answers
Determine whether a triangle with sides 12 cm, 14 cm and 18 cm is an acute, right or obtuse triangle.
Vanyuwa [196]
Obtuse... (Sorry it is not labeled) Not a right angle since it does not have a 90 degree angle neither acute since it isnt below 60 degree and obtuse due to being over 90 degree

4 0
3 years ago
Solve the proportion t+4 / t-2 = 1/4
Lera25 [3.4K]

t+4 / t-2 = 1/4

t=-6 for your answer!

8 0
4 years ago
What is the answer to this?
alexdok [17]

Answer:

  1. x < 2.5
  2. x > 2.5

Step-by-step explanation:

One way to do this is to try a number for x and see if it makes the inequality true. A suitable number here is x=0. This value of x is less than 2.5.

<h3>1.</h3>

For x=0, you have ...

  5 > -5 . . . . . true; the solution space is x < 2.5

__

<h3>2.</h3>

For x=0, you have ...

  -25 > -5(2.5)

  -25 > -12.5 . . . . . false; the solution space is x > 2.5

_____

<em>Alternate solution</em>

<h3>1.</h3>

Subtract 5:

  -4x > -10

Divide by -4

  x < 2.5

__

<h3>2.</h3>

Divide by -5:

  5 < x +2.5

Subtract 2.5

  2.5 < x

  x > 2.5

6 0
2 years ago
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