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zmey [24]
3 years ago
5

80 POINTS + BRAINLIEST !!!!!!!!

Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0

Solution:

we are given that

Clayton needs to reflect the triangle below across the line y=x.

And as we know the reflection of the point (x,y) across  the line y = x is the point (y, x).

Hence the new Traingle will be on the other side of the line y=x and position of x and y-coordinates of the vertices of the trangle gets interchanged.

Hence the Options that applies are:

C’ will move because all points move in a reflection.

The image and the pre-image will be congruent triangles. (Because reflection just changes the position of the trinagle not the property)

The image and pre-image will not have the same orientation because reflections flip figures.

GaryK [48]3 years ago
5 0

Point C’ will move because all points move in a reflection.  The image and the pre-image will be congruent triangles

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4.9t^2-2.78t-1.15=0 what is the value of T
zzz [600]

Answer:

t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

Step-by-step explanation:

Solve for t:

4.9 t^2 - 2.78 t - 1.15 = 0

4.9 t^2 - 2.78 t - 1.15 = (49 t^2)/10 - (139 t)/50 - 23/20:

(49 t^2)/10 - (139 t)/50 - 23/20 = 0

Multiply both sides by 10/49:

t^2 - (139 t)/245 - 23/98 = 0

Add 23/98 to both sides:

t^2 - (139 t)/245 = 23/98

Add 19321/240100 to both sides:

t^2 - (139 t)/245 + 19321/240100 = 75671/240100

Write the left hand side as a square:

(t - 139/490)^2 = 75671/240100

Take the square root of both sides:

t - 139/490 = sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

t = 139/490 + sqrt(75671)/490 or t - 139/490 = -sqrt(75671)/490

Add 139/490 to both sides:

Answer: t = 139/490 + sqrt(75671)/490 or t = 139/490 - sqrt(75671)/490

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3 years ago
What is 10% of 50 ??
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Answer:

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Step-by-step explanation:

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