Let
A------> <span>(1, 4)
B------> (6, 4)
C-----> (6,1)
we know that
In </span><span>a right triangle there are two legs and one hypotenuse
</span><span>
step 1
find the distance AB
d=</span>√[(y2-y1)²+(x2-x1)²]------> d=√[(4-4)²+(6-1)²]-----> d=√25----> 5
AB=5 units
step 2
find the distance BC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-6)²]-----> d=√9----> 3
BC=3 units
step 3
find the distance AC
d=√[(y2-y1)²+(x2-x1)²]------> d=√[(1-4)²+(6-1)²]-----> d=√34----> 5.83
AC=5.83 units
therefore
the two legs are
AB=5 units
BC=3 units
the hypotenuse is
AC=5.83 units
the answer is<span>
the length of the longer leg is AB=5 units
</span>
see the attached figure
The result of the product
is 
The product is given as:

Rewrite as:

Expand the expression on the right-hand side

Distribute the expressions

Evaluate like terms

Hence, the result of the product
is 
Read more about products at:
brainly.com/question/24963015
Answer:
I am not sure .but i will try
i think so i will give correct answer
perpendicular of triangle is 22-10 cm =12 cm bcz both sides of triangle are equal =22
area of rectangle l×w= 22×17=374
area of triangle =h×b/2 Now we r not having h
lets find it
use pythagorus theorum (h2=P2+b2....2 here is square)
h=22.5cm
22.5×19=427(area of triangle )
374+427=801cm sq
i tried my best dont know its righr of wrong
pls mark me as brainlieast
Answer:
it is letter B
Step-by-step explanation:
hope it helps you