3 years ago

WILL MARK YOU BRAINLIEST

Mathematics

1 answer:

kirza4 [7]3 years ago

5 0

Answer:

it is letter B

Step-by-step explanation:

hope it helps you

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if Donnie has 100 marbles and gives 25 away to Arthur and 35 to mike how many marbles does Donne have?

Marat540 [252]

Answer:

Step-by-step explanation:

100 MINUS 25 PLUS 35

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3 years ago

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Find the solution of the system of equations 2x-4y=32 2x-8y=48

Sveta_85 [38]

<span>2x-4y=32
2x-8y=48
--------------subtract
4y = - 16
y = -4

</span>2x-4y=32
2x- 4(-4)=32
2x + 16 = 32
2x = 16
x = 8

answer
(8, -4)

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4 years ago

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Tell whether it is possible to draw a triangle with the given side lengths. 4 cm, 4 cm, 7 cm

Sati [7]

Yes it is because 4+4=8 and 8 is larger than 7

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3 years ago

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Van purchased a DVD player on sale. The original selling price was

hammer [34]

Answer:

the first step is find the amount of money you saved

Step-by-step explanation:

171.50-145.12=26.38

26.38 / 171.5 = .154

15.4%

8 0

3 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

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3 years ago