Answer:
cells in mitosis go through the PMAT stages twice to produce diploid cells while cells in meiosis go through PMAT stages once to produce haploid cells, is. the best answer
George Monbiot is spearheading the Rewilding Movement. The environmentalist and writer is prominent in the platform. He was featured in TED Talk and talked about a large scale conservation approach aiming to restore the lost habitats. Here is an excerpt of his speech where he discusses the lost megafuna:
"What megafauna, you say? Well, every continent had one, apart from Antarctica. When Trafalgar Square in London was excavated, the river gravels there were found to be stuffed with the bones of hippopotamus, rhinos, elephants, hyenas, lions. Yes, ladies and gentlemen, there were lions in Trafalgar Square long before Nelson's Column was built. All these species lived here in the last interglacial period, when temperatures were pretty similar to our own. It's not climate, largely, which has got rid of the world's megafaunas. It's pressure from the human population hunting and destroying their habitats which has done so."
Mutualism is when both sides benefit. The hummingbird gets nectar and the flower is benefited because the hummingbird that has been to other flowers carry pollen on its body which spread the flower when it sucks its nectar, therefore pollinating the flower in the process.
Answer:
The muscles of the body is entirely made of proteins. They help in the making the connective tissue in the tendons of the body.
Explanation:
A. Making up the connective tissue in tendons
Answer:
1/8 (12.5%)
Explanation:
An autosomal recessive disease is an inherited disease in which an individual need to receive both defective alleles at the same gene <em>locus</em> to be expressed in the phenotype. In this case, both parents are carriers of the recessive mutant allele associated with the sickle cell anaemia trait, thereby both parents are heterozygous, ie., each parent has one copy of the normal allele 'H' and one copy of the defective mutant allele 'h' associated with this condition. In consequence, their first child has a 1/4 (25%) chance of having sickle-cell anaemia. Moreover, the chance of having a girl is 1/2 and the chance of having a boy is 1/2, thereby the final chance of having a girl sickle cell anaemia individual is 1/4 x 1/2 = 1/8 (12.5%).
- Parental cross for sickle cell anaemia trait = Hh x Hh >>
- F1 = 1/4 HH (normal); 1/2 Hh (normal); 1/4 hh (sickle cell anaemia) >>
- Sex proportion of sickle cell anaemia individuals = 1/8 female sickle cell anaemia individuals + 1/8 male sickle cell anaemia individuals (1/8 + 1/8 = 1/4)
