Answer:
<em>The answer to your question is </em><em>more force</em>
Explanation:
<em>A consequence of more mass having more inertia is that more force is required to bring the helicopter to the same speed as the bullet </em>
<u><em>I hope this helps and have a good day!</em></u>
Answer: the minimal force that you need to apply to move the bureau is F = 198.45N
Explanation:
If you want to move an object, you need to apply a force that is bigger than the force of the statical friction.
The force of statical friction can be written as.
Ff = k*N
where k is the coefficient of static friction, in this case, k = 0.45, and N is the normal force between the object and the surface.
In this case, the normal force is the weight of the bedroom bureau, this is:
N = m*g = 45kg*9.8m/s^2 = 441N
Then the force is:
Fr = 0.45*441N = 198.45N
This means that the minimal force that you need to apply to move the bureau is F = 198.45N
and after this point, the force of friction will work wit the kinetic coefficient of friction, that usually is smaller than the statical one.
The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
<h3>What current flows through the bulb as well as the power of the bulb?</h3>
From ohm's law; V = I × R
Where V is the voltage, I is the current and R is the resistance.
Also, Power is expressed as; P = V × I
Where V is voltage and I is current.
Given that;
- Resistance R = 10.0 ohms
- Voltage V = 12.0V
- Current I = ?
- Power P = ?
First, we determine the current flow through the bulb.
V = I × R
12.0V = I × 10.0 ohms
I = 12.0 ÷ 10.0
I = 1.2A
Next, we determine the power of the bulb.
P = V × I
P = 12.0V × 1.2A
P = 14.4 Watts
Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.
Learn more about Ohm's law here: brainly.com/question/12948166
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Answer:
the capacitive reactance is reduced by a factor 2
Explanation:
The capacitive reactance is given by:

where
f is the frequency of the source
C is the capacitance
In this case, the frequency of the source is doubled:
f' = 2f
while the capacitance does not change. So the new capacitive reactance will be

so the capacitive reactance is reduced by a factor 2.