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IRISSAK [1]
3 years ago
5

A hungry 173 kg lion running northward at 80.9 km/hr attacks and holds onto a 36.2 kg Thomson's gazelle running eastward at 63.8

km/hr. Find the final speed of the lion–gazelle system immediately after the attack.
Physics
1 answer:
slava [35]3 years ago
3 0

Answer:

77.9 km/h

Explanation:

We determine the initial momenta of lion and gazelle.

Lion: 173 × 80.9 = 13995.7

Gazelle: 36.2 × 63.8 = 2309.56

Since they are running in the same direction, we add their momenta to get the total initial momentum:

p_1 = 13995.7+2309.56 = 16305.26

After the collision, they are together and have a common velocity. Hence, the total final momentum is

p_2 = (173+36.2)\times v = 209.2v

By the principle of conservation of momentum, the total initial momentum is equal to the total final momentum, provided there are no external forces.

209.2v = 16305.26

v = \dfrac{16305.26}{209.2} = 77.9 \text{ km/h}

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An artificial satellite is moving in a circular orbit of radius 24,600 km. Calculate its speed if it takes 12hours to revolve ar
denis-greek [22]

Answer:

the speed of the satellite is 12,880.53 km/h

Explanation:

Given;

radius of the circular orbit, r = 24,600 km

time taken to revolve around Earth, t = 12 hours

The circumference of the satellite is calculated as;

L = 2πr

L = 2π x 24,600 km

L = 49,200π km

L = 154,566.36 km

The speed of the satellite;

v = L/t

v = 154,566.36 / 12

v = 12,880.53 km/h

Therefore, the speed of the satellite is 12,880.53 km/h

6 0
3 years ago
Pls help ASAP !! Phyics
mina [271]

Answer:

Explanation:

Given

mass (m)= 20 kg

acceleration (a)= 10 m/s^2

Force (f)= m a

             = 20 * 10

            = 200 N

7 0
3 years ago
A tourist averaged 82km/hr for a 6.5h trip in her volkswagen. how far did she go?
Whitepunk [10]
82 ÷ 6.5 = 12.615384615384... repeating
round = 12.6
12.6 · 6.5 = 81.9
round = 82
She went an average of 12.6 km an hour
Hope this helps! ;)
4 0
3 years ago
Two equipotential surfaces surround a +1.70 x 10-8-C point charge. How far is the 120-V surface from the 54.0-V surface?
UNO [17]

Answer:

1.55 m

Explanation:

The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

V =\frac{k*q}{r}

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.

Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:

r1 =\frac{k*q}{V1} = \frac{9e9 N*m2/C2*1.7e-8C}{120 V} = 1.28 m

r2 =\frac{k*q}{V2} = \frac{9e9 N*m2/C2*1.7e-8C}{54V} = 2.83 m

The distance between both points, is just the difference between the radius of both spheres, as follows:

r₂ - r₁ = 1.55 m

5 0
3 years ago
How much energy is created when there is 110 W of<br> power over 30s?
Makovka662 [10]

Answer:

3300 J

Explanation:
P = Q/t

Q = Pt = 110 * 30 = 3300 J

5 0
2 years ago
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