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ddd [48]
4 years ago
12

The literature value of the atomic mass of an isotope of nickel is 57.9 g/mol. If a laboratory experimenter determined the mass

to be 59.6 g/mol, what is the percent error?​
Chemistry
1 answer:
trapecia [35]4 years ago
3 0

Answer:

17%

Explanation:

Given parameters:

Atomic mass of nickel isotope = 57.9g/mol

Experimental value of atomic mass = 59.6g/mol

Unknown:

Percentage error in the measurement.

Solution:

The percentage error shows how much uncertainty was introduced into a measurement. To calculate this, we simply use the expression below:

Percentage error = \frac{Approximate atomic mass from expriment  - actual atomic mass}{actural atomic mass} x 100

Percentage error = \frac{59.6-57.9}{57.9}  x 100 = 17%

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The question is incomplete, here is the complete question:

A chemist prepares a solution of iron (III) bromide (FeBr_3) by measuring out 2.78 g of iron (III) bromide into a 50. mL volumetric flask and filling the flask to the mark with water.

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