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Wewaii [24]
3 years ago
5

Water often has dissolved gases and other chemicals in it. When this water encounters rocks, the minerals in the rocks can be ch

anged by the process of
Chemistry
1 answer:
babunello [35]3 years ago
5 0
Erosion is the best anwser for that
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What is the mole fraction of water in pure water
irinina [24]
In pure water, all of the molecules in the liquid are water molecules so the mole fraction is 1 (100 % H2O, 55 mol/L). In sea water, the concentration of water molecules in the solution is less than that of pure water so the vapor pressure of sea water is also lower.
5 0
3 years ago
How many photons are produced in a laser pulse of 0.497 J at 469 nm?
dimulka [17.4K]
<span>E=hν</span> where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by <span>λ=<span>cν</span></span>λ will have an energy given by <span>E=<span><span>hc</span>λ</span></span><span>λ=657</span> nm. This will be <span>E=<span><span>(6.626×<span>10<span>−34</span></span>)(2.998×<span>108</span>)</span><span>(657×<span>10<span>−9</span></span>)</span></span>=3.0235×<span>10<span>−19</span></span>J</span> So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or <span>N=<span><span>E<span>pulse </span></span><span>E<span>photon</span></span></span>=<span>0.363<span>3.0235×<span>10<span>−19</span></span></span></span>=1.2×<span>1018</span></span>So there would be <span>1.2×<span>1018</span></span><span> photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.</span>
7 0
3 years ago
Read 2 more answers
Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 45 L against a constant external pressure of
marta [7]

Answer:

Work done by the system = 4545 J

Explanation:

The expression for the calculation of work done is shown below as:

w=-P\times \Delta V

Where, P is the pressure

\Delta V is the change in volume

From the question,  

\Delta V = 45 - 15 L = 30 L

P = 1.5 atm

w=-1.5\times 30\ atmL

Also, 1 atmL = 101 J

So,  

w=-1.0\times0.75\times 101\ J=-4545\ J (negative sign implies work is done by the system)

<u>Work done by the system = 4545 J</u>

6 0
3 years ago
How can the prevailing winds be different during an El Nino year?
ad-work [718]

Answer: During an El Nino year, weakening winds along the equator lead to warming water surface temperatures that lead to further weakening of the winds

3 0
3 years ago
Read 2 more answers
A) The change in the internal energy of a system that absorbs 2,500 J of heat and that does 7,655 J of work on the surroundings
Phoenix [80]

Answers:

a) 10155 J

b) 16.6 J

Explanation:

According to the First Law of Thermodynamics we have:

\Delta E=Q + W

Where:

\Delta E is the total change in the internal energy of a system

Q is the heat exchanged between the system and its surroundings

W is the work done on the system

a) In this case Q=2500 J and W=7655 J, hence:

\Delta E=2500 J + 7655 J=10155 J

b) In this case Q=12.4 J and W=4.2 J, hence:

\Delta E=12.4 J + 4.2 J=16.6 J

5 0
3 years ago
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