The integer you’re looking for is 3
Answer:
(y^2+3y-28)/(4y^2-15y-4)
Step-by-step explanation:
(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)
= (y+7)(y-3)/(y-4)(4y+1)
= (y^2+3y-28)/(4y^2-15y-4)
all students who attend 1 MS and 1 HS in Miami, FL.
This is because they only surveyed 1 ms and 1 hs
Good luck! please vote me brainliest
2 and 1/2 - 1 and 1/2
since both equations have 1/2, 1/2 - 1/2 automatically is 0
then youll need to subtract 1 from 2 which is 1
Answer- 1
