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4 years ago

11

Solve for x. 10x2 – 20x – 8 = –5x2 – 6x

1 answer:

julia-pushkina [17]4 years ago

7 0

If that says 10x^2 and -5x^2 then the answer is x= -2/5, x=4/3
First get all the variables on one side, so you have 15x^2-14x-8=0. Use the abc factoring method and get factors 6 and -20.Since a is not one, you must group the factors like this (15x^2-20x)(6x-8). Factor those out to get 5x(3x-4)+2(3x-4). Now you put those together to get (5x+2)(3x-4). Set them equal to zero and solve for x. 5x+2=0 ends up being x=-2/5 and 3x-4=0 ends up being x=4/3. Hope that helps!

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Read 2 more answers

Gina has a jar of marbles that contains 7 blue marbles, 5 red marbles, and 8 green marbles. She randomly selects a marble, recor

BigorU [14]

The probability that Gina randomly selected two red marbles is 1/19

<u>Explanation:</u>

Total number of marbles = 7 + 5 + 8

= 20

The probability of getting two red marbles in the fraction form is given as:

P(first red marble) = number of red marbles / total number of marbles

P(first red marble) = $\frac{5}{20} = \frac{1}{4}$

P(second red marble) = number of red marbles after 1 white marble is removed / total number of marbles after 1 red marble is removed.

P(first red marble) = $\frac{4}{19}$

P(two red marbles) = P(first) X P(second)

= $\frac{1}{4} X \frac{4}{19}$

= $\frac{1}{19}$

Therefore, the probability that Gina randomly selected two red marbles is 1/19

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4 years ago

Find the area of a circle with radius, r = 7.49m. Give your answer rounded to 2 DP.

adell [148]

Answer:

Area ≈ 176.24m²

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3 years ago

. Joanne does a daily walk from building P to building Q. Given point P(6,9) and point Q(5,-4), what is the distance between poi

kotykmax [81]

Answer:

The distance between points P and Q on this campus map of the local college is 13.038 units

Step-by-step explanation:

We are given that Joanne does a daily walk from building P to building Q

$P=(x_1,y_1)=(6,9)\\Q = (x_2,y_2)=(5,-4)$

We are supposed to find the distance between points P and Q on this campus map of the local college

We will use distance formula :

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values in the formula .

$d=\sqrt{(5-6)^2+(-4-9)^2}\\d=13.038$

Hence the distance between points P and Q on this campus map of the local college is 13.038 units

5 0

4 years ago