Question d:
(D) Find the probability of F'nA'
Answer:
0.4140
0.7619
0.2381
0.9576
Step-by-step explanation:
Given that :
Female in fatal accident P(F) = 0.2805
Driver is 24 years or less P(A) = 0.1759
Driver is female and 24 years or less P(FnA) = 0.0424
A.) Find the probability of FUA.
P(FUA) = P(F) + P(A) - P(FnA)
= 0.2805 + 0.1759 - 0.0424
= 0.4140
(b) Find the probability of F'UA.
P(F'UA) = 1 - P(F) + P(FnA)
= 1 - 0.2805 + 0.0424
= 0.7619
C.) P(FnA') = 1 - P(F'UA)
= 1 - 0.7619
= 0.2381
(d) Find the probability of F'nA'
P(F'nA') = (FnA)' = 1 - (FnA)
= 1 - 0.0424
= 0.9576
Answer:
The percentage rate is 4.5%
Step-by-step explanation:
The simple interest earned in this situation is $1270 - $1000, or $270.
the simple interest formula is i =prt.
Here, i = $270 = ($1000)(r)(6 yr).
$270
Then r = ------------------- = 0.045
$1000(6 yr)
The percentage rate is 4.5%
200,000 is 20% of 1,000,000
Answer:
2
Step-by-step explanation:
Given the data : 29, 2, 28, 30, 26, 31
Outlier ;
Lower :Q1 - (1.5 * IQR)
Upper : Q3 + (1.5 * IQR)
Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range
Using calculator :
Q1 = 26
Q3 = 30
IQR = (Q3 - Q1) = 30 - 26 = 4
Lower : 26 - (1.5 * 4) = 20
Upper : 30 + (1.5 * 4) = 36
Hence, the number in the given data which falls outside the range is 2
