Answer: (see explanation)
Step-by-step explanation:
terms: 7, 2x, x4
leading coefficient: 7
constant term: 7
I'm sorry I'm unsure how to solve the last question.
Answer:
There's two of them, of which are the 3rd and 5th option
Step-by-step explanation:
The formula for calculating a prism is <em>length</em> times <em>width, </em>times the height because it is a 3d object. <em>Length</em> times <em>width</em> is the same as B(base), so those two are the exact same. Don't let that fool you.
Here's a little abstract context:
You've got one loaf of bread right? Well, pretend it's 3 inches by 4 inches. You have one slice, one layer, with 12 inches squared as its area. To make it a loaf, you stack the layers up by multiplying that slice of bread by the value of h.
(36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8"
This is the equation that you would get for the average. Now we just solve for z.
Following PEMDAS you have to mulitply the equation by 4 to get rid of the divide by 4 part.
4( (36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8)
Which does this
36 3/4" + 36 3/8" + 371/2" +z = 146 1/2"
Now you have to add and subtract to get "z" by itself.
36 3/4" + 36 3/8" + 371/2" = 110 5/8"
(110 5/8" + z = 146 1/2" ) -110 5/8"
z= 35 7/8", so the answer is b
Answer is 4 :) I hope it help you.
Answer:
The required recursive formula is
Step-by-step explanation:
Mohamed decided to track the number of leaves on the tree in his backyard each year.
The first year there were 500 leaves
Each year thereafter the number of leaves was 40% more than the year before so that means
For the third year the number of leaves increase 40% than the year before so that means
Similarly for fourth year,
So we can clearly see the pattern here
Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is
This is the required recursive formula to find the number of leaves for the nth year.
Bonus:
Lets find out the number of leaves in the 10th year,
So there will be 10330 leaves in the 10th year.
