Trina makes a diagram to summarize how to use the right-hand rule to determine the direction of the magnetic force on each type
of charge.
Which labels belong in the regions marked X, Y, and Z?
A) X: Thumb, for velocity
Y: Fingers, for magnetic field
Z: Palm of hand, for force
B) X: Back of hand, for force
Y: Thumb, for velocity
Z: Palm of hand, for force
C)X: Palm of hand, for force
Y: Thumb, for velocity
Z: Fingers, for magnetic field
D) X: Palm of hand, for force
Y: Fingers, for magnetic field
Z: Back of hand, for force
Which labels belong in the regions marked X, Y, and Z?
A) X: Thumb, for velocity
Y: Fingers, for magnetic field
Z: Palm of hand, for force
B) X: Back of hand, for force
Y: Thumb, for velocity
Z: Palm of hand, for force
C)X: Palm of hand, for force
Y: Thumb, for velocity
Z: Fingers, for magnetic field
D) X: Palm of hand, for force
Y: Fingers, for magnetic field
Z: Back of hand, for force
2 answers:
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Answer:
14,700 N
Explanation:
The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:
(1)
the weight of the hyppo is
where m is the hyppo's mass and g is the gravitational acceleration; therefore, solving eq.(1) for N, we find
The magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C. The principal of the Columb's law is used in the given problem.
<h3>What is Columb's law?</h3>The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.
They will repel, moving in opposite directions at the same speed. Because the magnitude and nature of the charge are the same.
The given data in the problem is;
q₁ is the charge 1 = 4.4 nC = 4.4 ×10⁻⁹ C
F is the repulsive force = 36 mN =36 ×10⁶ N
d is the distance = 0.70 m
The Coulomb force is found as;
Hence, the magnitude and sign of the second charge will be + 8.6241×10⁻¹⁹ C.
To learn more about Coulomb's law, refer to the link;
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