Answer:
(a) 8.362 rad/sec
(b) 6.815 m/sec
(c) 9.446
(d) 396.22 revolution
Explanation:
We have given that diameter d = 1.63 m
So radius
Angular speed N = 79.9 rev/min
(a) We know that angular speed in radian per sec
(b) We know that linear speed is given by
(c) We have given final angular velocity
And
Time t = 63 sec
Angular acceleration is given by
(d) Change in angle is given by
Answer:
The amount of electrons that flow in the given time is 3.0 C.
Explanation:
An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.
i.e I = ...................(1)
It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.
In the given question, I = 1.5A, t = 2s, find Q.
From equation 1,
Q = I × t
= 1.5 × 2
= 3.0 Coulombs
The amount of electrons that flow in the given time is 3.0 C.
Answer:
The beam used is a negatively charged electron beam with a velocity of
v = E / B
Explanation:
After reading this long statement we can extract the data to work on the problem.
* They indicate that when the beam passes through the plates it deviates towards the positive plate, so the beam must be negative electrons.
* Now indicates that the electric field and the magnetic field are contracted and that the beam passes without deviating, so the electric and magnetic forces must be balanced
q E = qv B
v = E / B
this configuration is called speed selector
They ask us what type of beam was used.
The beam used is a negatively charged electron beam with a velocity of v = E / B