Answer:
The angular velocity at the beginning of the interval is
.
Explanation:
Given that,
Angular acceleration ![\alpha=\pi\ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D%5Cpi%5C%20rad%2Fs%5E2)
Angular displacement ![\theta=\pi\ rad](https://tex.z-dn.net/?f=%5Ctheta%3D%5Cpi%5C%20rad)
Angular velocity ![\omega =2\pi\ rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D2%5Cpi%5C%20rad%2Fs)
We need to calculate the angular velocity at the beginning
Using formula of angular velocity
![\alpha =\dfrac{\omega^2-\omega_{0}^2}{2\theta}](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cdfrac%7B%5Comega%5E2-%5Comega_%7B0%7D%5E2%7D%7B2%5Ctheta%7D)
![\omega_{0}^2=\omega^2-2\alpha\theta](https://tex.z-dn.net/?f=%5Comega_%7B0%7D%5E2%3D%5Comega%5E2-2%5Calpha%5Ctheta)
Where,
= angular acceleration
= angular velocity
Put the value into the formula
![\omega_{0}^2=(2\pi)^2-2\times\pi\times\pi](https://tex.z-dn.net/?f=%5Comega_%7B0%7D%5E2%3D%282%5Cpi%29%5E2-2%5Ctimes%5Cpi%5Ctimes%5Cpi)
![\omega=\sqrt{2\pi^2}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B2%5Cpi%5E2%7D)
![\omega_{0}=\pi\sqrt{2}\ rad/s](https://tex.z-dn.net/?f=%5Comega_%7B0%7D%3D%5Cpi%5Csqrt%7B2%7D%5C%20rad%2Fs)
Hence, The angular velocity at the beginning of the interval is
.
Answer:
These energy exchanges are not changes in kinetic energy. They are changes in bonding energy between the molecules. "If heat is coming into a substance during a phase change, then this energy is used to break the bonds between the molecules of the substance
Answer:
<h2>Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.</h2>
<h3>Fundamental quantities are the base quantities of a unit system, and they are defined independent of the other quantities. </h3>
Explanation:
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![\\ \blue{MaggieEve}](https://tex.z-dn.net/?f=%5C%5C%20%5Cblue%7BMaggieEve%7D)
Answer:
C
Explanation:
Angular momentum is the product of moment of inertia and angular velocity.
L = I × ω
Since the planet follows a stable circular orbit, I and ω are constant and non-zero. Therefore, the angular momentum is constant and non-zero.