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2 years ago

Object B has a mass of 8 kg and was lifted at a rate of 3 m/s. What is the kinetic energy of object B?

Physics

1 answer:

Greeley [361]2 years ago

5 0

Answer:36J

Explanation:

mass=m=8kg

Velocity=v=3m/s

Kinetic energy=ke

Ke=0.5 x m x v x v

Ke=0.5 x 8 x 3 x 3

Ke=36

Kinetic energy is 36J

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The equation for gear ratio

Ymorist [56]

In a gear train with two gears, the gear ratio is defined as follows
$R= \frac{\omega _A}{\omega _B}$

where $\omega _A$ is the angular velocity of the input gear while $\omega _B$ is the angular velocity of the output gear.

This can be rewritten as a function of the number of teeth of the gears. In fact, the angular velocity of a gear is inversely proportional to the radius r of the gear:
$\omega = \frac{v}{r}$
But the radius is proportional to the number of teeth N of the gear. Therefore we can rewrite the gear ratio also as
$R= \frac{\omega _A}{\omega _B} = \frac{r_B}{r_A} = \frac{N_B}{N_A}$

4 0

3 years ago

A 240 V circuit has 20 A flowing through it. How much power is it using?

Delvig [45]

Explanation:

P = IV

V = 240

I = 20

P = ?

P = 240 × 20

P = 4800 watts

6 0

3 years ago

(20 points) You are at the center of a boat and have been rowing the boat for a long time. You weigh only 80 kg and your 120 kg

valina [46]

Answer:

Explanation:

From the given information:

Let the first weight be $m_ 1$ = 80 kg

The weight of the buddy be $m_2$ = 120 kg

The weight of Bubba be $m_3$ = 60 kg

Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:

$x_1 = x_3 = \dfrac{4}{2} \\ \\ = 2$

The length of the boat be $x_2$ = 4 m

∴

We can find the center of mass of the system by using the formula:

$X_{CM} = \dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X_{CM} = \dfrac{(80 \times 2)+(120\times4)+(60\times2)}{80+120+60} \\ \\ X_{CM} = \dfrac{160+480+120}{260} \\ \\ \mathbf{X_{CM} = 2.923}$