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densk [106]
3 years ago
5

Object B has a mass of 8 kg and was lifted at a rate of 3 m/s. What is the kinetic energy of object B?

Physics
1 answer:
Greeley [361]3 years ago
5 0

Answer:36J

Explanation:

mass=m=8kg

Velocity=v=3m/s

Kinetic energy=ke

Ke=0.5 x m x v x v

Ke=0.5 x 8 x 3 x 3

Ke=36

Kinetic energy is 36J

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The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 o
shepuryov [24]

Complete Question

The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is  less than 4 ounce.

Answer:

Yes the true mean weight is less than 4 ounce

Explanation:

  From the question we are told that

     The random sample is n = 15

       The mean weight is \= x = 3.8\  ounce

        The standard deviation is  \sigma = 0.5 \ ounce

         The  level of significance is  \alpha  = 0.05

       

So

   The  null hypothesis is  H_o : \mu \ge 4

     The alternative hypothesis is H_a : \mu < 4

Generally the critical value which a bench mark to ascertain whether the null hypothesis is  true or false is mathematically represented as

            t_{0.05} = 1.79

This value is  obtained from  the critical value table

Generally the test statistics is mathematically represented as

                Test \ Statistics (ST)  = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} }  }

           =>  ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }

                ST = - 1.79

So since ST is less than t_{0.05}  then the null hypothesis would be rejected and the alternative hypothesis would be accepted so

  Thus the true mean weight is less than 4

4 0
3 years ago
Why is magnesium the limiting reactant in this experiment
Keith_Richards [23]

Answer:

Explanation:

  • Magnesium is being oxidized by the oxygen in the air to magnesium oxide. This is a highly exothermic combustion reaction, giving off intense heat and light. The reaction of the combustion of magnesium in oxygen is given below:
  •                                     2Mg(s) + O2(g) → 2MgO(s)
  • The stoichiometric factor is 2 moles of magnesium are burned for every 1 mole of oxygen (2mol Mg/1mol O2). If the magnesium strip weighs 1 gram, then there is 0.04 mol of magnesium (1 gram divided by 24.3 grams/mol Mg) available in the reaction. The amount of oxygen required to completely react with the magnesium strip is:
  • 0.04 mol Mg x (1 mol O2 / 2 mol Mg) = 0.02 mol O2 x 16 g/mol O2 = 0.32 gram O2.
  • The magnesium will burn until consumed entirely. There is much more oxygen available in the atmosphere than needed to consume the magnesium. Thus the magnesium is the limiting reactant because it determines the amount of product formed.
4 0
3 years ago
How can geo thermal energy be used ?​
jek_recluse [69]

Answer:

Geothermal energy can heat, cool, and generate electricity: Geothermal energy can be used in different ways depending on the resource and technology chosen—heating and cooling buildings through geothermal heat pumps, generating electricity through geothermal power plants, and heating structures through direct-use

Explanation:

5 0
1 year ago
Read 2 more answers
The primary coil of a transformer contains 100 turns; the secondary has 200 turns. The primary coil is connected to a size aa ba
tester [92]

Answer:

3 volts

Explanation:

Number of turns in primary coil = N_{p} = 100

Number of turns in secondary coil = N_{s} = 200

Voltage across primary coil = V_{p} = 1.5 volts

Voltage across secondary coil = V_{s} = ?

In a transformer, the ratio of number of turns of primary to secondary coil is equal to the ratio of the respective voltages i.e.

\frac{N_{p} }{N_{s} } =\frac{V_{p} }{V_{s} }\\

Using the given values, we get:

\frac{100}{200}=\frac{1.5}{V_{s} }\\V_{s}=1.5 \times \frac{200}{100}\\V_{s}=3

Thus, the voltage measure across secondary coil would be 3 volts

4 0
3 years ago
How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?
Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

7 0
3 years ago
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