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densk [106]
3 years ago
5

Object B has a mass of 8 kg and was lifted at a rate of 3 m/s. What is the kinetic energy of object B?

Physics
1 answer:
Greeley [361]3 years ago
5 0

Answer:36J

Explanation:

mass=m=8kg

Velocity=v=3m/s

Kinetic energy=ke

Ke=0.5 x m x v x v

Ke=0.5 x 8 x 3 x 3

Ke=36

Kinetic energy is 36J

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Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm fro
k0ka [10]

The ray diagram for the given object consists of 2 cm height of object, 4 cm object distance and 3 cm focal length.

<h3>Image formed by a diverging lens</h3>

Diverging lens is called a concave lens. The working of the lens is dependent on the refraction of the light rays as they pass through the lens.

Image formed by a diverging lens is always virtual, erect and diminished; smaller than the object and is located on the same side of the lens as the object.

The ray diagram for the given object is presented in the image in the diagram.

  • Object height = 2 cm
  • Focal length = 3 cm
  • Object distance = 4 cm

Learn more about diverging lens here: brainly.com/question/3140453

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8 0
2 years ago
A box experiences a force of 2 N to the left and 3 N to the right. Which is true of the box's motion?
Nostrana [21]
Below are the choices:

<span> A) The box will slow down.
B) The box's velocity will be 1 m/s.
C) The box's velocity will not change.
 D) The box will experience acceleration 
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The answer is D) The box will experience acceleration 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
5 0
3 years ago
Read 2 more answers
A 1900kg car starts from rest and drives around a flat 65-m-diameter circular track. The forward force provided by the car's dri
s344n2d4d5 [400]

Answer:

The\quad magnitude\quad of\quad the\quad car's\quad acceleration\quad at\quad t=13s\quad \quad =2.52m/{ s }^{ 2 }\\ The\quad direction\quad of\quad the\quad car's\quad acceleration\quad at\quad t=13s\quad =15.{ 72 }^{\o}\\The\quad car\quad begins\quad to\quad slide\quad out\quad \quad of\quad the\quad circle\quad after\quad 26.09s.\quad \quad \quad \quad

Explanation:

8 0
3 years ago
A bicyclist bikes the 90 mi to a city averaging a certain speed. The return trip is made at a speed that is 1 mph slower. Total
Lynna [10]

Answer:

his speeds while going to city is 10 mph and while his round trip the speed will be 9 mph

Explanation:

Let say the speed of the bicycle while he moves towards the city is "v"

now the speed of the round trip must be smaller by 1 mph

so its speed for round trip will be

v_2 = v - 1

now we know that total time of the motion is 19 hr

so we will have

t_1 = \frac{90}{v}

t_2 = \frac{90}{v - 1}

so we will have

t_1 + t_2 = 19 hr

\frac{90}{v} + \frac{90}{v-1} = 19

90(2v - 1) = 19(v^2 - v)

19 v^2 - 199 v + 90 = 0

by solving above equation we have

v = 10 mph

so his speeds while going to city is 10 mph and while his round trip the speed will be 9 mph

5 0
3 years ago
Which one is it<br> Plz help me :)
Gennadij [26K]

Answer:

5 I think will be none of the above and 6 could be all of the above

8 0
3 years ago
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