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Paha777 [63]
2 years ago
14

Show that if S1 and S2 are subsets of a vector space V such that S1 c S2 then span(S1) c span(S2). In particular, if S1 c S2 the

n Span(S1)
Mathematics
1 answer:
klemol [59]2 years ago
5 0

Answer:

See proof below

Step-by-step explanation:

Assume that V is a vector space over the field F (take F=R,C if you prefer).

Let x\in span(S_1). Then, we can write x as a linear combination of elements of s1, that is, there exist v_1,v_2,\cdots,v_k \in S_1 and a_1,a_2,\cdots,a_k\in F such that x=a_1v_1+a_2v_2+\cdots+a_kv_k. Now, S_1\subseteq S_2 then for all y\in S_1 we have that y\in S_2. In particular, taking y=v_j with j=1,2,\cdots,k we have that v_j\in S_2. Then, x is a linear combination of vectors in S2, therefore x\in span(S_2). We conclude that span(S_1)\subseteq span(S_2).

If, additionally  S_2\subseteq S_1 then reversing the roles of S1 and S2 in the previous proof, span(S_2)\subseteq span(S_1). Then span(S_1)\subseteq span(S_2)\subseteq span(S_1), therefore span(S_1)=span(S_2).

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juin [17]
The nth term of the geometric sequence is:
an=ar^(n-1)
where 
a=first term
r=common ratio
n=nth term
from the question:
120=ar(3-1)
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a=120/(r^2)....i
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