Question

Find the equation of the quadratic function with zeros 10 and 12 and vertex at (11, -2).

Answer 1

Answer:

$y=2x^2-44x+240$

Step-by-step explanation:

we are given a quadratic equation

Let's assume formula of vertex form of parabola as

$y=a(x-h)^2+k$

where vertex is (h,k)

we are given

vertex =(11,-2)

so, h=11, k=-2

now, we can plug it

$y=a(x-11)^2-2$

now, we are given zeros at x=10 and x=12

we know that zeros will be x=10 , y is 0

so, we can plug x=10 and y=0 and solve for 'a'

$0=a(10-11)^2-2$

$0=a-2$

$a=2$

now, we can plug it back

and we get

$y=2(x-11)^2-2$

so, we get quadratic equation as

$y=2x^2-44x+240$