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nikklg [1K]
3 years ago
11

Find the equation of the quadratic function with zeros 10 and 12 and vertex at (11, -2).

Mathematics
1 answer:
Tanya [424]3 years ago
6 0

Answer:

y=2x^2-44x+240

Step-by-step explanation:

we are given a quadratic equation

Let's assume formula of vertex form of parabola as

y=a(x-h)^2+k

where vertex is (h,k)

we are given

vertex =(11,-2)

so, h=11, k=-2

now, we can plug it

y=a(x-11)^2-2

now, we are given zeros at x=10 and x=12

we know that zeros will be x=10 , y is 0

so, we can plug x=10 and y=0 and solve for 'a'

0=a(10-11)^2-2

0=a-2

a=2

now, we can plug it back

and we get

y=2(x-11)^2-2

so, we get quadratic equation as

y=2x^2-44x+240

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