Answer:
10 times
Step-by-step explanation:
The 8 in 1,857 is in the hundreds place and the 8 in 3,083 is in the tens place.
Answer:
2/8
Step-by-step explanation:
2/8 or 1/4
The price of ticket last year is $ 1231.65
<em><u>Solution:</u></em>
Given that,
This year, Sophia paid $1,071 for season tickets to her favorite baseball team , which is 15% cheaper than last year
To find: Price of season ticket last year
Let the price of season ticket last year be "x"
Therefore, according to question
Price of ticket this year is 15 % cheaper than price of ticket last year
1071 = price of ticket last year - 15 % of 1071
1071 = x - 15 % of 1071
Solve the above expression for "x"
Thus price of ticket last year is $ 1231.65
Let's make clear the question:
"<span>During August, Boxer Company sells $364,000 in merchandise that has a one year warranty. Experience shows that warranty expenses average about 5% of the selling price. The warranty liability account has a credit balance of $12,000 before adjustment. Customers returned merchandise for warranty repairs during the month that used $8,600 in parts for repairs. The entry to record the estimated warranty expense for the month is:
a) Debit Estimated Warranty Liability $18,200; credit Warranty Expense $18,200.
b) Debit Warranty Expense $6,200; credit Estimated Warranty Liability $6,200. c) Debit Warranty Expense $18,200; credit Estimated Warranty Liability $18,200.
d) Debit Warranty Expense $14,800; credit Estimated Warranty Liability $14,800.
e) Debit Estimated Warranty Liability $8,600; credit Warranty Expense $8,600." </span>
First, calculate the average warranty expenses:
364000 × 5 ÷ 100 = 18200$
This amount has to be recorded both as a debit (debit warranty expenses) and as a credit (credit estimated warranty liability).<span>
Therefore, the correct answer is:
</span><span>c) Debit Warranty Expense $18,200; credit Estimated Warranty Liability $18,200.</span>
You are given an expression for y, so put that expression where y is in the first equation.
... 12x -5(x+4) = -20 . . . . . x+4 substituted for y
... 12x -5x -20 = -20 . . . . eliminate parentheses
... 7x = 0 . . . . . . . . . . . . . . collect terms, add 20
... x = 0 . . . . . . . . . . . . . . divide by 7
... y = x +4 = 0 +4 = 4 . . . put the value of x into the expression for y
The solution is x=0, y=4.