<span>Lactic Acid Fermentation and Alcoholic Fermentation. Lactic Acid fermentation produces lactic acid, and alcoholic fermentation produces alcohol and carbon dioxide.Lactic acid fermentation has 2 ATP. Oxygen is required for the process to occur-Aerobic means. No oxygen is required for the process to occur-Anaerobic means. The ferment sugar which produces ethanol, methanol, and only a little ATP.</span>
Answer:
Cancerous cells possess defects that make proteins required for cell growth active and tumor suppressor genes inactive.
Stem cells arise from the inner mass of the cell
Signalling factors trigger differentiation in stem cells
Genes that lead to the production of undifferentiated blood cells are activated
Signalling factors cause undifferentiated blood cells to produce red blood cells
Explanation:
Red blood cells are formed in the bone marrow. The precursor to the RBC is stem cell which is undifferentiated and pluripotent. The stem cell gets differentiated to form immature RBCs. Immature RBC then gets divided and becomes mature. Stem cell giving rise to RBC is called Haemoctytoblast. The process of erythropoiesis takes 2 days to form new red blood cells
Answer:
allelic frequency a = 30%
allelic frequency A = 70%
Explanation:
You are studying a population of sparrows in which the phenotype is determined by a single locus. Only two alleles for this locus are known for this population, which are distinguished by the codes 'A' and 'a'. The distribution of phenotypes in the population indicates that 49% of the population is homozygous 'AA', 42% is heterozygous and 9% 'aa' homozygous. How is the allele frequency for 'A' and 'a' determined based on these observations?
According to the case, the allelic frequency for A and a will be searched with the data:
homozygotes AA = 49%
heterozygotes Aa = 42%
homozygous aa = 9%
Frequency of homozygotes 'aa'
(q 2) = 9/100 = 0.09
we can obtain the allelic frequency of a through the following formula:
a (q) = √0.09
The result will be
= 0.3
we change to percentage
= 30%
we have the following formula
p + q = 1
to find the allele frequency A, represented by p
p = 1 - 0.3
we get the following result
p = 0.7
we change to percentage
= 70%
