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Rzqust [24]
2 years ago
14

Janice works a babysitting job and makes $30 dollars a night. She babysits approximately 3 nights a week. What is her annual inc

ome from babysitting? REMEMBER IT SAYS ANNUAL
Mathematics
1 answer:
34kurt2 years ago
4 0

Answer:

her annual income is $360

Step-by-step explanation:

$360

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What is the equation of a line that is perpendicular to y=4x-5 and passes through (-4,6)
lozanna [386]

Answer:

y=-1/4x+5

Step-by-step explanation:

perpendicular lines have slopes that multiply to -1.

Our given line:

y=4x-5

the slope (m) in it is 4. To find the slope of the perpendicular line:

4m=-1

divide by 4

m=-1/4

the slope of the new line is -1/4

here's our equation so far:

y=-1/4x+b

Since the line will pass through the point (-4,6) we can use it to solve for b (y intercept)

so substitute (-4,6) into the equation

6=-1/4(-4)+b

6=1+b

5=b

the y intercept is 5

so our equation is:

y=-1/4x+5

hope this helps! :D

4 0
3 years ago
Please I need to get this done by tomorrow
Alenkinab [10]

Answer:

i think it is 8

4 0
3 years ago
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How long will it take you to drive 175 miles of 25 miles per hour
Paha777 [63]
So if you're driving 25 miles per hour, it would take you 7 hours to drive 175 miles. 175 miles ÷ 25 miles = 7 hours.
8 0
3 years ago
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Determine whether the relation is a function or not. (-2-8). (-1.-4), (1,4),(2,8), (3, 12) function not a function​
sveticcg [70]

Answer:

ill explain

Step-by-step explanation:

find the difference between the y and x values

5 0
3 years ago
A researcher is planning to compare the effects of two different types of lights on the growth of bean plants. She expects that
kicyunya [14]

Answer:

The sample size is  n  = 36

Step-by-step explanation:

From the question we are told that

   The sample standard deviation is  s =  1.5

  The mean difference of the two groups is  \=x _ 1 - \=x_2 =  1

   The standard error is  SE =  \frac{ \= x_1 - \= x_2}{4}

=>                                      SE =  \frac{1}{4}

Let assume that the confidence level is 95% hence the level of significance is  

   \alpha = (100-95)\%

=> \alpha = 0.05

So the critical value of  \frac{\alpha }{2} obtained from the normal distribution table is

     Z_{\frac{\alpha }{2} } = 1.96

Generally the margin of error is mathematically evaluated as

     E =  Z_{\frac{\alpha }{2} } * SE    

   E =  1.96 * \frac{1}{4}

    E = 0.49

Generally the sample size is mathematically represented as

  n =[ \frac{Z_{\frac{\alpha }{2}  * s^2}}{E}]^2

=> n  = [\frac{1.96 * 1.5}{0.49} ]^2

=> n  = 36

6 0
3 years ago
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