Question

Identify the method that will be used to solve for x for each equation.

Answer 1

Answer:

for 4x = 20 you have to use the division property of equality divide 20 by 4

for x - 11 = 9 you have to use the addition property of equality add 9 to 11

for 5x + 6x = 22 you have to combine like terms add 5x and 6x to make 11x

for 5(x – 2) = 30 you have to use the distributive property multiply 5 and x; 5 and -2

4x = 20; x = 5

x - 11 = 9; x = 20

5x + 6x = 22; 11x = 22; x = 2

5(x – 2) = 30; 5x - 10 = 30; x = 8

Answer 2

For this case we have:

Equation 1:

$4x = 20$

Dividing between 4 on both sides of the equation we have:

$\frac {4x} {4} = \frac {20} {4}\\x = 5$

Equation 2:

$x-11 = 9$

Adding 11 to both sides of the equation we have:

$x-11 + 11 = 9 + 11\\x = 20$

Equation 3:

$5x + 6x = 22$

We add similar terms to the left side of the equation:

$11x = 22$

We divide between 11 on both sides of the equation:

$\frac {11x} {11} = \frac {22} {11}\\x = 2$

Equation 4:

$5 (x-2) = 30$

We apply distributive property of the left side of the equation we have:

$5x-10 = 30$

Adding 10 to both sides of the equation:

$5x-10 + 10 = 30 + 10\\5x = 40$

Dividing between 5 on both sides of the equation:

$\frac {5x} {5} = \frac {40} {5}\\x = 8$

ANswer:

$x = 5\\x=20\\x = 2\\x = 8$