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olga nikolaevna [1]

3 years ago

8

The smallest natural number divisible by 2, 3, 4, 5, 6, 7, 8, 9, is

2 answers:

Andrew [12]3 years ago

8 0

Answer:

2

Step-by-step explanation:

<em>thi</em><em>s</em><em> </em><em>is</em><em> </em><em>bec</em><em>ause</em><em>,</em>

<em>natu</em><em>ral</em><em> </em><em>num</em><em>bers</em><em> </em><em>are</em><em> </em><em>numbers</em><em> </em><em>that</em><em> </em><em>begins</em><em> </em><em>fr</em><em>om</em><em> </em><em>1</em><em> </em><em>to</em><em> </em><em>infin</em><em>ity</em>

<em>and</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>set</em><em> </em><em>of</em><em> </em><em>num</em><em>bers</em><em> </em><em>above</em>

<em>all</em><em> </em><em>of</em><em> </em><em>the</em><em>m</em><em> </em><em>are</em><em> </em><em>natu</em><em>ral</em><em> </em><em>num</em><em>bers</em>

<em>and</em><em> </em><em>from</em><em> </em><em>tho</em><em>se</em><em> </em><em>num</em><em>bers</em><em>,</em><em> </em><em>the</em><em> </em><em>one</em><em>s</em><em> </em><em>whi</em><em>ch</em><em> </em><em>are</em><em> </em><em>divi</em><em>sible</em><em> </em><em>by</em><em> </em><em>2</em><em> </em><em>are</em>

<em>{</em><em>2</em><em>,</em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>}</em>

<em>and</em><em> </em><em>from</em><em> </em><em>these</em><em> </em><em>num</em><em>bers</em><em>,</em>

<em>the</em><em> </em><em>small</em><em>est</em><em> </em><em>on</em><em>e</em><em> </em><em>is</em><em> </em><em>2</em><em>.</em>

Vlada [557]3 years ago

3 0

The smallest natural number divisible by 2 is 2. 2 divided by 2 is 1. Or 4 divided by 2 is 2 which divided by 2 is 1.

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Answer:

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Step-by-step explanation:

Given:

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= ?

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