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3 years ago

7

Sonia received a statement on her Certificate of Deposit showing that her investment had returned $4,320 over its life. If the C

ertificate of Deposit pays a simple interest rate of 4.8% and her initial investment was $12,000, how long had the money been invested?

1 answer:

bija089 [108]3 years ago

6 0

Answer:

The correct answer is -7.5 years.

Step-by-step explanation:

Given:

Principle amount = 12000

Interest = 4320

time = ?

rate = 4.8 simple interest

Solution:

We know that simple Interest I = (P*t*r)/100

then t = I*100/p*r

putting values in formula:

t = 4320*100/4.8*12000

= 432000/57,600

= 7.5 years

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Step-by-step explanation:

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3 years ago

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Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

<em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using <em>factorization</em> method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using <em>factorization</em> method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is $2y^{2} (y+ 10)$ .

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

$HCF \times LCM = p \times q$

Using equations <em>(1)</em> and <em>(2)</em>: $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, <em>LCM</em> = $8y^{4}(y+ 10)^{2}(y + 8)$

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3 years ago

If $10,000 is invested in an account at 4.8% annual simple interest, how long will it take for the account balance

Lesechka [4]

10000+4.8%=10480
10480+4.8%=10983.04
10983.04+4.8%=11510.22592

so 3 years

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3 years ago

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The original price of a pair of shoes at Nike Outlet is 109.99 and there is a mark down of 25% because the shop is having a blac

marissa [1.9K]

Answer:

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Step-by-step explanation:

109.99=100%

10.999=10%

21.998=20%

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so they are taking £27.4975 off the original price meaning the new price is £82.4925 but, because it is money, you would need to round this to two decimal places leaving the new price as £82.49

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3 years ago

Find the equation of the line that passes through point (6, 1) with the x-intercept of 2.

34kurt

<u>Answer:</u>

○ $y = \frac{1}{4}x - \frac{1}{2}$

<u>Step-by-step explanation:</u>

To find the equation of the line, let's first consider the points whose coordinates we have been given:

• (6, 1)

• (2, 0).

The point (2, 0) is what is called the x-intercept, which is the point where the line crosses the x-axis. This means that at this point, the y-coordinate of the line is 0.

Next, let's calculate the slope (gradient) of the line using the formula:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

where:

m = gradient,

$(x_2, y_2)$ and $(x_1, x_2)$ = points on the line.

Using the formula:

$m = \frac{1 - 0}{6 - 2}$

⇒ $m =\bf \frac{1}{4}$

Finally, now that we have two points on the line as well as the line's slope, we can use the following formula to find the equation of the line:

$\boxed{y - y_1 = m(x - x_1)}$

You can use any of the points on the line as $y_1$ and $x_1$ .

Using (2, 0):

$y - 0 = \frac{1}{4}( x - 2)$

⇒ $y = \frac{1}{4}x - \frac{1}{2}$

Therefore the equation of the line is $y = \frac{1}{4}x - \frac{1}{2}$ .

Learn more about point-slope form at:

brainly.com/question/15143525

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2 years ago