Part (a) Finding the probability of either A or B
We are told that events A and B are mutually exclusive. This means they cannot happen at the same time. We can say P(A and B) = 0
Furthermore,
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 0.4 + 0.2 - 0
P(A or B) = 0.6
<h3>Answer: 0.6</h3>
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Part (b) Finding the probability of neither A nor B
P(A or B) + P(neither A nor B) = 1
P(neither A nor B) = 1 - P(A or B)
P(neither A nor B) = 1 - 0.6
P(neither A nor B) = 0.4
The reason why this works is to imagine throwing a dart at the Venn diagram. You'll either...
- you land in A or B (pick one but not both), OR,
- you'll land outside both regions A and B.
One or the other must happen. Both events cannot happen simultaneously.
<h3>Answer: 0.4</h3>
Answer:
No solution.
Step-by-step explanation:
6(n −1) + 2 = n(4 + 2) + 4
6n - 6 + 2 = 6n + 4
-4 = 4 (inconsistency)
6750/125= 1% of the goal
6750/125= 22
54*100 would equal 100% of their goal.
54*100=5400
Their goal was $5400
Hope this helps :)
Empirical rule dictates that, in a Bell-shaped distribution, 95% of data lies within 2 standard deviation on either side of the mean.
Therefore,
Lower value = mean-2SD = 70-2*8 = 70-16 = 54
Upper value = mean+2SD = 70+2*8 = 70+16 = 86
Then, 95% of the data lies between $54 and 84. These values can also be taken as the true mean of the population considering 95% confidence when sample mean has been calculated. In this regard, 2SD can be regarded as the margin error.
Simplify the expression
The answer is 9
