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STALIN [3.7K]
3 years ago
15

PLEASE HELP ME ASAP ;(

Computers and Technology
1 answer:
Pavel [41]3 years ago
7 0

Answer:

It is D

Extra words here

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Does the estimate of a tolerance level of 68.26% of all patient waiting times provide evidence that at least two-thirds of all p
ivanzaharov [21]

Answer:

Yes, because the upper limit is less Than 8 minutes

Explanation:

According to the empirical formula :

68.26% of data lies within 1 standard deviation from the mean;

Hence,

Mean ± 1(standard deviation)

The sample mean and sample standard deviation of the given data is :

Sample mean, xbar = Σx / n = 546 / 100 = 5.46

Sample standard deviation, s = 2.475 (Calculator)

The interval which lies within 68.26% (1 standard deviation is) ;

Lower = (5.460 - 2.475) = 2.985

Upper = (5.460 + 2.475) = 7.935

(2.985 ; 7.935)

Since the interval falls within ; (2.985 ; 7.935) whose upper level is less than 8 means patients will have to wait less Than 8 minutes.

8 0
3 years ago
• What is the difference between primary storage, secondary storage, and off-line storage
sergiy2304 [10]


Primary storage refers to your RAM it is internal storage.

Secondary storage is any storage that is not the primary storage that permanently stores data. Examples are hard drive, tape disk drive, floppy disk drive  and compact disk drive. 

Off-line storage refers to any device that stores data that is not permanently attached to the computer. Example flash drives, The data remains on the storage device and can be connected to a different computer. 

3 0
3 years ago
Friday Night Funkin Fans, does this count as a leak if I share it?
Aliun [14]
Hmm no I don’t think so
7 0
2 years ago
Read 2 more answers
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
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<span>A wiki is this type of site. The users can, anonymously or with a profile, add to or delete content already posted. This gives the community the ability to add to the overall knowledge base on a specific subject. The site tracks changes through IP addresses to make sure that changes are not done maliciously.</span>
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3 years ago
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