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If BC= 48 cm and sin

erastovalidia [21]

Using relations in a right triangle, it is found that the length of AC is of 14 cm.

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.

The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.

The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

Researching this problem on the internet, we have that:

The opposite leg to angle A is of 48 cm.

sin(A) = 0.96.

Hence the hypotenuse is found as follows:

sin(A) = 48/h

0.96 = 48/h

h = 48/0.96

h = 50 cm.

The length of side AC is the other leg of the triangle, found using the Pythagorean Theorem, hence:

$x^2 + 48^2 = 50^2$

$x^2 = \sqrt{50^2 - 48^2}$

x = 14 cm.

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

6 0

2 years ago

Pedro bought 8 tickets to a basketball game. He paid a total of $208. Write an equation to determine whether each ticket cost $2

Kryger [21]

Here is the equation:

8x= 208

Divide both sides by 8.

x= 26

Each ticket costs 26 dollars.

I hope this helps!
~kaikers

3 0

3 years ago

Read 2 more answers

A hyperbola centered at the origin has verticies at (add or subtract square root of 61,0 and foci at (add or subtract square roo

deff fn [24]

Answer:

$\frac{x^2}{61}-\frac{y^2}{37} =1$

Step-by-step explanation:

The standard equation of a hyperbola is given by:

$\frac{(x-h)^2}{a^2} -\frac{(y-k)^2}{b^2} =1$

where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²

Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)

The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61

The foci is (h ± c, k) = (±√98, 0). Therefore c = √98

Hence:

c² = a² + b²

(√98)² = (√61)² + b²

98 = 61 + b²

b² = 37

b = √37

Hence the equation of the hyperbola is:

$\frac{x^2}{61}-\frac{y^2}{37} =1$

6 0

3 years ago

HELP PLS ASAP!

Leokris [45]

Step-by-step explanation:

The horizontal stretch or compression for a function f(x) is given by g = f(bx) where b is a constant. If b> 0 then the graph of a function is compressed.

As it is given in the question that the function is transformed by a compression factor of 3.

Given function

The value of k will be 3 if the function is transformed by a compression factor of 3

3 0

3 years ago

The following octagon is formed by removing four congruent right triangles from a rectangle. What is the area of each triangle?

andriy [413]

Try this formula(n-2)180/n (n is number of sides)

6 0

4 years ago