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nadezda [96]
3 years ago
12

Suppose a parabola has vertex (–8, –7) and also passes through the point (–7, –4). Write the equation of the parabola in vertex

form.

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0
That’s the answer and also the steps to getting that answer

You might be interested in
mariah owed her grandfather $2.25 but was only able to pay him back 1.50 , how much does mariah currently owe her grandfather
aleksandr82 [10.1K]

Answer:

0.75 cents

Step-by-step explanation:

You take...

$2.25 and subtract $1.50 to get 0.75 cents

In-depth...

Start off with taking a dollar away...

2.25 - 1.00 = 1.25

Then take off 0.50 cents...

We know that 0.50 cents are two 0.25 cents

So, we take off one 0.25 cent

1.25 - 25 = 1.00

Then the next 0.25 cents

*Remember: twenty-five (.25), fifty (.50), seventy-five (.75), a dollar (1.00)

<--- it is just adding 25 each time

If we subtract 0.25 cents from a dollar we get...

0.75 cents

3 0
2 years ago
Read 2 more answers
1. The measure of side c is 150 feet and the
marishachu [46]

Answer:

Hi...

a^2+b^2=c^2

b^2=c^2-a^2

b^2=22500-3600=18900

So...b=137/4

7 0
3 years ago
Lines that meet or cross each other to form square corners are called ______.
Viefleur [7K]

The lines that intersect to form square corners that are right angles are called: C. perpendicular lines.

<h3>What are Perpendicular Lines?</h3>

Perpendicular lines are lines that intersect each other at a point and forms for square corners that are right angles at that point of intersection.

An example of perpendicular lines is shown in the image attached below.

Thus, the lines that meet to form right angles are called: C. perpendicular.

Learn more about perpendicular lines on:

brainly.com/question/1202004

#SPJ1

5 0
1 year ago
X/8 -5 &lt;-2 how do I solve this to make it true
sdas [7]
First you would add 5 to both sides
X/8=3
Then multiply both sides by 8
X=24
7 0
3 years ago
Help plz!!!! Thx !!!!
Blizzard [7]
3 outa 12 are 5 
so we divide 150 by 12
Hence Getting 25. 
So 25 Is the Answer

I Hope I Helped :)
7 0
3 years ago
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