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3 years ago

7

Need help on a question 3 yards =blank inches

2 answers:

earnstyle [38]3 years ago

6 0

The answer to your questions 108 inches because there are three feet in one yard (3-feet=one-yard). There are 12 inches in one foot so (12-inches=1-foot). 12 inches for the 1 foot times the 1 yard will give you 36 inches=3-feet. 36 inches times the 3 yards will give you your answer.

worty [1.4K]3 years ago

3 0

3 feet are in 1 yard so 36 inches times 3 is.....108 inches!

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The nth term of a sequence is given by 2n²+1.Write down the first four terms of the sequence.

ivanzaharov [21]

Answer:

2(1)²−1= 1

2(2)²−1= 7

2(3)²−1= 17

2(4)²−1= 31

2(5)²−1= 49

<em><u>Please mark as brainliest if answer is right </u></em>

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3 years ago

Jane is training for a triathlon. After swimming a few laps, she leaves the health club and bikes 16 miles south. She then runs

lianna [129]

Answer:

The equation for the distance Jane's trainer bikes is $x=\sqrt{16^2+12^2}$ .

Step-by-step explanation:

We have attached diagram for your reference.

Given:

Distance traveled on bike towards south = 16 miles

Distance she ran towards west = 12 miles

We need to find distance Jane's trainer bikes.

Solution:

Let the distance Jane's trainer bike be 'x'.

Now we will assume it to be right angled triangle.

So by Pythagoras theorem which states that;

"Square of the third side is equal to the sum of square of the other two sides."

framing in equation form we get;

$x^2=16^2+12^2\\\\x=\sqrt{16^2+12^2}$

Hence the equation for the distance Jane's trainer bikes is $x=\sqrt{16^2+12^2}$ .

On solving we get;

$x=\sqrt{16^2+12^2}\\\\x= \sqrt{256+144}\\ \\x=\sqrt{400} \\\\x=20\ miles$

Hence Jane's trainer bikes a distance of 20 miles.

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3 years ago

Write a system of linear equations for the graph below.

sp2606 [1]

<h2>Answer:</h2>

We need to determine the equation of both lines first.

Line 1: <em>y = -2x + 3</em>

Line 2: <em>y = -1/3x - 2</em>

Now that we know the equations, we can set up a system of equations for this graph where both equations are in standard form.

Line 1:

$y = -2x + 3\\\\2x + y = 3$

Line 2:

$y = -\frac{1}{3}x - 2\\\\\frac{1}{3}x + y = -2$

<em>Final answer:</em>

$2x + y = 3\\\frac{1}{3}x + y = -2$

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faltersainse [42]

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