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kakasveta [241]
2 years ago
13

Isaac was having cookies and milk with his

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
4 0

Answer:

There is now 3 cups of m ilk left in the jug.

Step-by-step explanation:

12+1=13 | 13-16=3

ANSWER: 3

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Answer this question with a clear explanation to be marked as Brainiest ✨✨✨✨✨✨✨✨
Nina [5.8K]

Answer:

C

Step-by-step explanation:

A, B and D are all only a few digits long and can be expressed as the ratio of two integers, where at least one is even:

A = -6/16 = -3/8, so it's rational

B = 7.0398 = 35199/5000, so it's rational

D = 6,907 = 13814/2, therefore rational

C, on the other hand is irrational.

If we simplify the surd √8, we get 2√2. The 2's on the top and bottom can now cancel out, giving us √2, which is irrational. [There's a proof but it's kinda long].

5 0
1 year ago
What is the product of the rational expressions below
ankoles [38]
The answer to the question is a
8 0
2 years ago
D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
2 years ago
find the values of x and y that make these triangles congruent by the hl theorem x=2,y=3 x=-2,y=3x=3,y=2x=4,y=8
AnnyKZ [126]

Answer:

The correct option is x=3 , y=2

Step-by-step explanation:

According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

Now we will plug the value y+1 of equation 1 in equation 2.

2x+3 = 3y+3

2(y+1)+3=3y+3

2y+2+3=3y+3

2y+5=3y+3

Now combine the like terms:

5-3=3y-2y

2=y

y=2

Now plug the value y=2 in equation 1.

x=y+1

x=2+1

x=3

Thus the values of(x.y) are{(2,3)}

Therefore the correct option is x=3 , y=2 .....

3 0
3 years ago
-3z-z answer please fast​
ch4aika [34]

Answer:

-4z

Step-by-step explanation:

4 0
3 years ago
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