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2 years ago

The bottom one says 13 btw

Mathematics

1 answer:

andriy [413]2 years ago

8 0

Answer:

Step-by-step explanation:

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ANSWER ASAP PLZ

Helen [10]

Choice B is the answer because:
2*2=4
4*2=8
8*2=16
16*2=32
32*2=64
or
2^6= 64

5 0

2 years ago

Read 2 more answers

Ai Mi went to the store to buy some chicken. The price per pound of the chicken is $3.50 per pound and she has a coupon for $2.5

oksian1 [2.3K]

Answer:

$8 for 3 pounds

cost for p pounds: 3.50p - 2.50

Step-by-step explanation:

Cost of 3 pounds:

Original cost = Cost per pound x 3

= 3.50 x 3

= 10.50

Coupon = 2.50

Final cost = Original cost - Coupon

= 10.50 - 2.50

= $8

Cost of p pounds:

Original cost = Cost per pound x p

= 3.50 x p

= 3.50p

Coupon = 2.50

Final Cost = Original Cost - Coupon

= 3.50p - 2.50

3 0

2 years ago

6(8f+10g) + 9g - 4(3g+9f)

Karolina [17]

Answer:84f+57g

Step-by-step explanation:

First, multiply everything in parenthesis.

Multiply the 6 by 8f+10g, and the 4 by 3g+9f.

This gets you 48f+60g+9g-12g+36f.

After that, just solve it like normal.

You get 84f+57g.

8 0

9 months ago

Which is an appropriate estimate

saveliy_v [14]

Answer:

Step-by-step explanation:

This answer is the closest when it comes to 3,844 divided by 75.

6 0

2 years ago

Read 2 more answers

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

$P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630$

$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0

2 years ago