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sergejj [24]
3 years ago
15

Please help ASAP! What is the Value of X?

Mathematics
1 answer:
Nataly [62]3 years ago
7 0

Answer:

  • 4x+7=5x-20
  • 7+20=5x-4x
  • x=27°

hope it helps.

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The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

8 0
3 years ago
HELP!!!<br> ANSWER FAST. PLEASEEE
kari74 [83]

Answer:

The answer would be $2.

Have a nice day.

4 0
3 years ago
Read 2 more answers
Please help ASAP<br><br> If f(x) = x^2-6x+2 and g(x) =sqrt x find a.) (fog) (x)<br> b.) (gof) (-2)
Rudik [331]
\large\begin{array}{l} \left\{\!\begin{array}{l} \mathsf{f(x)=x^2-6x+2}\\ \mathsf{g(x)=\sqrt{x}}\\ \end{array}\right. \end{array}


\large\begin{array}{l} \textsf{a) }\mathsf{(f\circ g)(x)}\\\\ =\mathsf{f\big[g(x)\big]}\\\\ =\mathsf{\big[g(x)\big]^2-6\cdot g(x)+2}\\\\ =\mathsf{\big[\sqrt{x}\big]^2-6\sqrt{x}+2}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(f\circ g)(x)=x-6\sqrt{x}+2} \end{array}}\qquad\checkmark \end{array}

______


\large\begin{array}{l} \textsf{b) }\mathsf{(g\circ f)(-2)}\\\\ =\mathsf{g\big[f(-2)\big]}\\\\ =\mathsf{\sqrt{f(-2)}}\\\\ =\mathsf{\sqrt{(-2)^2-6\cdot (-2)+2}}\\\\ =\mathsf{\sqrt{4+12+2}}\\\\ =\mathsf{\sqrt{18}}\\\\ =\mathsf{\sqrt{3^2\cdot 2}}\\\\ =\mathsf{3\sqrt{2}}\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{(g\circ f)(-2)=3\sqrt{2}} \end{array}}\qquad\checkmark \end{array}

______


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2181559


\large\textsf{I hope this helps. :-)}


Tags: <em>composite function composition evaluate algebra</em>

7 0
3 years ago
Evaluate the expression for s = -15. -S= ​
Oxana [17]

Answer:

  -S = 15

Step-by-step explanation:

You are asked to find the opposite of the given value.

<h3>Opposite</h3>

The opposite of an integer value is obtained by changing its sign.

  S = -15

  -S = -(-15) = 15

__

<em>Additional comment</em>

Equivalently, you are multiplying by -1. The product of an even number of minus signs is a plus sign. We usually don't write the plus sign for a numerical value.

3 0
1 year ago
Please help it's been like 30 mins and I'm so confused.
lbvjy [14]

1s = 13m

1 * 3 = 13 * 3

= 3s = 39 m

10 s = 13 * 10 => 130

So, 1) 1s

      2) 3s

      3) 130m

8 0
2 years ago
Read 2 more answers
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