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stellarik [79]
3 years ago
8

Fill in the other coordinate for the line 3x-5y=2: (4, )

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0
Plug in 4 for X
3(4)-5y=2
12-5y=2
-12 (both sides)
-5y=-10
divide both by -5
y=2

the coordinates are (4,2)
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Sarah ate 22 of them
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The two angles illustrated in the picture are what kinds of angles?
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A Rectangle with sides 100m and 50m. Person B and Person A start walking in the opposite direction at the same point with veloci
Maurinko [17]

Answer:

It takes takes them 31.67 secs to meet after Person A starts walking

OR

34.67 secs after Person B starts walking

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First, we will find the perimeter of the rectangle

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Perimeter of the rectangle = 2 (100+50)

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Hence, the perimeter of the rectangle is 300m

This is the total distance that will be covered by both persons by the time they meet.

Let the distance covered by person A be S_{1}

and the distance covered by person B be S_{2}

We can write that

S_{1} + S_{2} = 300m

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and velocity of person B, V_{B} = 5 m/s

From the question, Person A starts walking 3 seconds after person B,

This means, if person A spends t secs before they meet, then person B would spend (3 + t) secs.

For Person A,

Velocity = 4 m/s

Time = t secs

Distance = S_{1}

From,

Velocity = \frac{Distance}{Time}

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Distance = Velocity \times time

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S_{1} = 4t ...... (1)

For Person B

Velocity = 5 m/s

Time = (t + 3) secs

Distance = S_{2}

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S_{2} = 5 \times (3+t)

S_{2} = 5(3+t) ...... (2)

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Then, S_{2} = 300m - S_{1}

We can then write that,

300m - S_{1} = 5(3+t)

Then,

S_{1} = 300 - 5(3+t) ..... (3)

Equating equations (1) and (3), we get

300 - 5(3+t) = 4t

300 - 15 -5t = 4t\\9t = 285\\t = \frac{285}{9}\\

t = 31.67 secs

This is the time spent by Person A

Hence, it takes takes them 31.67 secs to meet after Person A starts walking OR

34.67 secs after Person B starts walking

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