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Ostrovityanka [42]
3 years ago
11

Which object has the mass of about one kilogram?

Mathematics
2 answers:
stira [4]3 years ago
7 0

Answer:

A dictionary has the mass of about 1 killo so the book!

Step-by-step explanation:

Alexandra [31]3 years ago
5 0

Answer:

Step-by-step explanation:

The dictionary

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Write the function , √(x^3+6)/√(x^3-9) as a composition of three or more non-identity functions.
tamaranim1 [39]

Answer:

h \circ m \circ n \text{ where } h(x)=\sqrt{x} \text{ and } m(x)=1+\frac{15}{n} \text{ and } n(x)=x^3-9

Step-by-step explanation:

Ok so I see a square root is on the whole thing.

I'm going to let the very outside function by h(x)=sqrt(x).

Now I'm can't just let the inside function by one function g(x)=\frac{x^3+6}{x^3-9} because we need three functions.

So I'm going to play with g(x)=\frac{x^3+6}{x^3-9} a little to simplify it.

You could do long division. I'm just going to rewrite the top as

x^3+6=x^3-9+15.

g(x)=\frac{x^3-9+15}{x^3-9}=1+\frac{15}{x^3-9}.

So I'm going to let the next inside function after h be m(x)=1 + \frac{15}{x}.

Now my last function will be n(x)=x^3-9.

So my order is h(m(n(x))).

Let's check it:

h(m(x^3-9))

h(1+\frac{15}{x^3-9})

h(\frac{x^3-9+15}{x^3-9})

h(\frac{x^3+6}{x^3-9})

\sqrt{ \frac{x^3+6}{x^3-9}}

3 0
3 years ago
The International Business Club starts the school year with $250.50 in their account. They spend $35 each month on activities. T
Julli [10]

Answer:

m= 4.8 months

Step-by-step explanation:

by taking  x as the money the International Business Club has at any time of the year,250.5 for their initial money, 35 as the money they spend every month and m being the month that have passed since the beginning of the school year; it all can be related to the following equation:  

x= 250.5 - (35*m)

And doing the same thing with the money from the Future Agricultural Leaders Club, associating their money to the variable y, the equation would be:

y=300 - (45.25*m)

as it is wanted to know at what month does both clubs have the same amount of money, x and y, must be the same, so:

250.5 - (35*m)  =300  - (45.25*m)

this equation can be solved by putting both terms that are related to m on the same side of the equality, and those who aren’t related on the other side:

(45.25*m)  - (35*m)= 300  -250.5

then, on the first side of the equation, m  can be taken out as common factor:

(45.35-35)*m=49,5

and solving for m:

m=\frac{49.5}{10.25}

m=4.8  

5 0
4 years ago
When is the additive relationship used? Select all that apply.
Mrac [35]

Answer:

your answer is for sure D but I think C is also the answer

Step-by-step explanation:

Additive relationship are two quantities can be expressed as related to each other through addition. It can be written as y = x + a, where y is related to x through the addition of a constant, a. The value for a may be positive or negative.

7 0
3 years ago
Read 2 more answers
2. Evaluate: 6.231 x 10^3 <br>​
Vlad [161]

Answer:

6.231 × 10³

= 6.231 × 1000

= 6231

Step-by-step explanation:

brainliest plz

8 0
3 years ago
Koji is installing a rectangular window in a office building, the window is
VladimirAG [237]
4983/<span>100 


49 and 83/100 feet^2


hope I helped!

Let me know if you need anything else!

~ Zoe</span>
4 0
3 years ago
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