Answer:
The range of the function is:
Range R = {14, 17, 20}
Step-by-step explanation:
Given the function
We also know that range is the set of values of the dependent variable for which a function is defined.
In other words,
- Range refers to all the possible sets of output values on the y-axis.
We are given that the domain of the function is:
Domain D = {4, 5, 6}
Now,
substituting x = 4 in the function
f(4) = 3(4) + 2
f(4) = 12 + 2
f(4) = 14
substituting x = 5 in the function
f(5) = 3(5) + 2
f(5) = 15 + 2
f(5) = 17
substituting x = 6 in the function
f(6) = 3(6) + 2
f(6) = 18 + 2
f(6) = 20
Thus, we conclude that:
at x = 4, y = 14
at x = 5, y = 17
at x = 6, y = 20
Thus, the range of the function is:
Range R = {14, 17, 20}
<span>So far I have:
(1.25 + 1) </span><span>if </span>x<span> is in the interval</span><span> (-inf,7]
(2.25 +1) </span><span>if </span>x<span> is in the interval (7,13)</span><span>
(3.50+1+3) </span><span>if </span>x<span> is in the interval [13,inf)</span>
Answer:
-935160312
Step-by-step explanation:
Step-by-step explanation:
Add 1 to both sides
Multiply both sides by 4
Take the square root of both sides
Subtract 5 from both sides
(straight from khan academy hints)