Ask question

Ask question

All categories

3 years ago

5

An eagle is flying at a height of 275 feet and climbing at a rate of 65 feet per second. The equation for the height of the bird

y is y=275+65x,where x is the number.of seconds in flight. What do the slope and y- intercept represent? why?

1 answer:

77julia77 [94]3 years ago

7 0

The slope represents the how fast the bird is climbing and the Y intercept represents where the bird started to climb

You might be interested in

Check my math work please, use photo attached

Sonja [21]

Answer:

The department total on the bottom right hand side should be 464253. Everything else is correct.

Step-by-step explanation:

Adding was wrong across the bottom row.

3 0

3 years ago

You need to create a 4-character password that consists of four English letters and/or digits if repetition is allowed. How ma

Nataly_w [17]

123a
123q
123w
123e
123r
123t
123y
123u
123i
123o
123p
123s
123d
123f
123g
123h
123j
123k

I thought this would be easy lol, I tried, sorry for not getting an answer

3 0

3 years ago

Trey’s car has a 20-gallon fuel tank. The fuel gauge points to ¼ . If Trey buys 10 gallons of gas, what will be the new reading

Lelu [443]

Answer:

3/4

Step-by-step explanation:

1/4 + 2/4 = 3/4

5 + 10 = 15

6 0

4 years ago

Read 2 more answers

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

5 0

3 years ago

Read 2 more answers

Plz do this all plz

Taya2010 [7]

Answer:

I don't know search it up I picked B

okay it's 5 and I'm

6 0

3 years ago