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Maksim231197 [3]
3 years ago
12

Which of the following is a list of unlike terms, or terms that cannot be combined?

Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer:

C

Step-by-step explanation:

C is the only choice where all given options have different or no coefficients.

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Find the zero of the linear function f(x)=x+5
inn [45]

Answer:

-5 =x

Step-by-step explanation:

f(x)=x+5

Set the function equal to zero

0 = x+5

Solve for x

-5 = x+5-5

-5 =x

7 0
3 years ago
Angles X and Y are supplementary. Angle X is 3 times the measure of angle Y. What is the measure of angle X?
Andreas93 [3]

we know that

Supplementary angles are those angles whose sum is equal to 180 degrees

In this problem

x+y=180 --------> equation 1

x=3y --------> equation 2

Substitute the equation 2 in equation 1

[3y]+y=180

4y=180

y=45°

<u>Find the value of x</u>

x=3*45

x=135°

therefore

<u>the answer is </u>

The measure of angle x is 135°


4 0
3 years ago
Read 2 more answers
A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has
cluponka [151]

Answer:!!

Step-by-step explanation:!!

8 0
3 years ago
X+2y=-8 find the slope ​
laila [671]

Answer:

 Slope = -1.000/2.000 = -0.500

 x-intercept = -8/1 = -8.00000

 y-intercept = -8/2 = -4

Step-by-step explanation:

Step  1  :

Equation of a Straight Line

Graph of a Straight Line

Calculate the Y-Intercept

Calculate the Slope

Calculate the X-Intercept

<em><u>Answer: </u></em>Slope = -1.000/2.000 = -0.500

<em><u>Hope this helps.</u></em>

7 0
3 years ago
Read 2 more answers
Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of
Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

\triangle ABC \sim \triangle NMP

MP\parallel BC

MP=\frac{BC}{2}

By the property of similar triangles,

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}

Hence proved.

5 0
3 years ago
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