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elena55 [62]
2 years ago
13

How do you find the Interquartile of a box and whiskers plot?

Mathematics
1 answer:
Ann [662]2 years ago
4 0

Answer:

In a box and whisker plot, there is a rectangle (box) with a line in the middle of it. The middle is the mean. The interquartile values are the ends of the rectangle (the lower one -- 25% -- to the left and the higher one -- 75% -- to the right).

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What number is 300% of six
nadya68 [22]

Answer:

18

Step-by-step explanation:

100% of 6 is 6 so 300% (which does not actually exist) would be 3 times as much. 6x3=18

6 0
3 years ago
Read 2 more answers
Help me asap
pogonyaev

Answer:

6J = 72

Step-by-step explanation:

Because it says the product, it is talking about multiplication.

J would be Jamelle's age

6 is the excess number given.

72 is the answer

thus it would be 6*J or 6J = 72

4 0
2 years ago
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Aileen can read 1.5 pages for every page her friend can read. Aileen's mom was very excited and she said to Aileen: "So, if your
jolli1 [7]
No, because here mom is adding in 3.5 more pages when it say only 1.5. So she'll be able to read 30 pages because 1.5 and 20 pages of her friends is 30. So your answer is that her mom is wrong.

I hope this helped! I gave an explanation and an answer. You're Welcome!
8 0
3 years ago
Read 2 more answers
Write the difference 16 -(-53) as a sum then simplify
valina [46]

Answer:

<h2>69</h2>

Step-by-step explanation:

(-)(-) = (+)

(+)(+) = (+)

(-)(+) = (+)(-) = (-)

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16 - (-53) = 16 + 53 = 69

3 0
3 years ago
An ant looks to the top of a bulding at an angle of elevation of 32°. The ant then walks an additional 66 feet from the edge of
Keith_Richards [23]
Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4

Therefore, the height of the building is 75.4 feet.
8 0
2 years ago
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