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3 years ago

What is the answer of question 16 Please help me and I put you brainest

Mathematics

1 answer:

Vikentia [17]3 years ago

5 0

Answer:

12 m 2600 mm

Step-by-step explanation:

3 m × 4 = 12 m

650 mm × 4 = 2600 mm

Hope this helps!

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PLEASE HELP DONT ANSWER IF YOU DONT KNOW....

Damm [24]

Answer:

5.7 Round it and you will get that

4 0

3 years ago

Read 2 more answers

James estimate the product of 48 and 53 is that reasonable

Debora [2.8K]

50 x 50= 2500.............

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3 years ago

Antonette gets $70\%$ on a 10-problem test, $80\%$ on a 20-problem test and $90\%$ on a 30-problem test. If the three tests are

notka56 [123]

Answer:

Percentage score will be 83.33 %

Step-by-step explanation:

We have given Antonette gets 70 % on 10 problem test

Let consider here here total problem = total marks

So marks get 10 10 problem test = 10×0.7 = 7

Marks get in 20 problem test = 20×0.8 = 16

And marks get in 30 problem test = 30×0.9 = 27

Now total marks get get by Antonette = 7 +16 + 27 = 50

And total marks = 60

So percentage score of Antonette $=\frac{50}{60}\times 100=83.33$ %

8 0

3 years ago

A rabbit population doubles every 4 weeks. There are currently five rabbits in a restricted area. If t represents the time, in w

Mumz [18]

98 days = (98 ⁄ 7) weeks = 14 weeks

Po = initial population = 5 

Ƭ = doubling time in weeks 

t = elapsed time in weeks 

P{t} = population after "t" weeks 

 P{t} = (Po)•2^(t ⁄ Ƭ) 

 P{t} = (Po)•2^(t ⁄ 4) 

 P{t} = 5•2^(t ⁄ 4) 

 P{14} = (5)•2^(14 ⁄ 4) … t = 14 weeks = 98 days 

 P{14} = 56 … population after 14 weeks

6 0

3 years ago

5. Solve using any method. y = -x + 8 y=x+4

vlada-n [284]

Answer:

Step-by-step explanation:

$\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

$\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

7 0

3 years ago