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4 years ago

What is 12/20 simplified as much as can be

2 answers:

7 0

3/5 is 12/20 simplified. :)

1. Find the greatest common factor of 12 and 20 which is 4.
2. Divide 12 by 4 and 20 by 4.
3. 12/4=3 and 20/4=5
4. 3/5!

sesenic [268]4 years ago

5 0

$\frac{12}{20}$ (simplify the 4)
$12$ ⇒ $12:4$
$20$ ⇒ $20:4$
⇒ $\frac{3}{5}$
The answer is: $\frac{3}{5}$

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15. *Free response. GCO2. After examining the following graph, Kate claims that WXYZ is translated

jonny [76]

D =works , equal lateral

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4 years ago

What is the prime factorization of 11

daser333 [38]

Answer:

11=11*1

Step-by-step explanation:

Eleven is a prime number, you can see that by proving with other minor prime numbers. like 2,3, 5 and 7

Neighter of those divide exactly 11, except 1

3 0

4 years ago

Exercise 5.2. Suppose that X has moment generating function

soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) $M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Step-by-step explanation:

Given:

moment generating function of X as:

MX(t) = $\frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}$

a) Now

Mean, E(X) = $M_{X}'(t=0)$

Thus,

$M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}$

$M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}$

also,

$E(X^{2})=M_{X}''(t=0)$

Thus,

$M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}$

$M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}$

Therefore,

Mean, E(X) = $M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}$

Mean, E(X) = - 0.5

and

$E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}$

$E(X^{2})$ = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

$M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Therefore,

at x = 0, P(x) = $\frac{1}{2}$

at x= - 4 ,P(x) = $\frac{1}{3}$

at x = 5, P(x) = $\frac{1}{6}$

Thus,

E(X) = $\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})$

E(X) = - 0.5

also, $E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})$

$E(X^{2})$ = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0

4 years ago

Given the function g(x) = 8x −2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two val

Maru [420]

G(x) = 8x - 2

g(-2) = 8(-2) - 2 = -16 - 2 = -18

g(4) = 8(4) - 2 = 32 - 2 = 30

3 0

3 years ago

a student's cost for last semester in her community college was $2,300. she spent $253 of that on books. what percent of my seme

lana66690 [7]

Answer:

11%

Step-by-step explanation:

To find the percentage of books to total cost, divide 253/2300. You get .11

Move the decimal 2 places to the right and that's the percentage.

11%

hope this was good enough

4 0

3 years ago