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Brums [2.3K]
2 years ago
6

enter fair.each ride costs$2.50. you have $21.50. how many rides can you go on? Type your equation. Let x = number of rides

Mathematics
1 answer:
lord [1]2 years ago
4 0

Answer:

x=8

Step-by-step explanation:

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$2.95 is the answer to question e
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3 years ago
#2, can someone help me with this question?
Greeley [361]

Answer:

166.5 m³

Step-by-step explanation:

Vcone = ⅓ × pi × r² × h

pi × r² × h = 3 × Vcone

Vcylinder = pi × r² × h

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8 0
3 years ago
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Identify the value of y<br><br><br> (3y+5)=-4-8y+9+77
noname [10]

Answer:

Y=7

Step-by-step explanation:

(3y+5)= -4 -8y +9 + 77

     -5    -5            

    3y= -9 - 8y + 9 + 77

           +9          -9

    3y=  -8y + 77

    +8y    +8y

      11y = 77

      11y/11    77/11

        y = 7

1. subtract 5 from both sides

2. add -9 and +9 and you get 0

3. add 8y to both sides

4. divide both sides by 11

5. you get y=7

3 0
3 years ago
A number cube has faces numbered 1 through 6, and a coin has two sides, "heads" and "tails". The
Mama L [17]

Answer:

The <em>required probability</em> is \dfrac{1}{12}.

Step-by-step explanation:

Let <em>A </em>be the event of rolling the number cube.

Let <em>B</em> be the event of tossing the coin.

Total number of possibilities of rolling the number cube and tossing the coin are <em>12 </em>here.

\{(1,H),(2,H),(3,H),(4,H),(5,H),(6,H),(1,T),(2,T),(3,T),(4,T),(5,T),(6,T)\}

where <em>H</em> means Head on toss of coin and <em>T</em> means Tails on toss of coin.

Formula for probability of an event <em>E</em> is:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, we have to find the probability of event 'E' i.e. getting a 6 on number cube and heads on coin.

Number of favorable cases are <em>1 </em>and total cases are <em>12</em>.

\Rightarrow P(E) = \dfrac{1}{12}

6 0
2 years ago
How many are 15 x 15 ?​
marissa [1.9K]

Answer:

225

Step-by-step explanation:

8 0
2 years ago
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