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2 years ago

I really need help with this please

Mathematics

2 answers:

Morgarella [4.7K]2 years ago

6 0

It is always because a hypothesis is a if answer

marshall27 [118]2 years ago

3 0

The hypothesis is sometimes the if part in my opinion

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HELP DUE TODAY!!!!!!

larisa [96]

Answer:

x° is 66°

Step-by-step explanation:

From the given diagram, we have;

∠JIH = 105° Given

∠IDJ = 39° Given

Therefore, we have;

∠JID and ∠JIH are supplementary angles, by the sum of angles on a straight line

∴ ∠JID + ∠JIH = 180° by definition of supplementary angles

∠JID + 105° = 180° by substitution property

∠JID = 180° - 105° = 75° by angle subtraction postulate

∠JID = 75°

∠IDJ + ∠JID + ∠IJD = 180° by the sum of interior angles of a triangle

∠IJD = 180° - (∠IDJ + ∠JID) = 180° - (39° + 75°) = 66° angle subtraction postulate

∠IJD = 66°

∠x° ≅ ∠IJD, by vertically opposite angles

∴ ∠x° = ∠IJD = 66° by the definition of congruency

∠x° = 66°

7 0

2 years ago

Read 2 more answers

Slope =<br> ; y-intercept = -3

Goshia [24]

Question is incomplete Let assume the Slope = 2

Answer:

Therefore the Equation of line is

$y=2x -3$

Step-by-step explanation:

Given:

Slope = 2 ( Assumption )

y-intercept = -3

To Find:

Equation of Line in Slope-intercept form

Solution:

Equation of Line in Slope-intercept Form is given as

$y=mx+c$

Where,

$m=Slope\\c=y-intercept$

So, substituting Slope =2 and y-intercept = -3 in above we get

$y=2\times x -3$ Which is the Required Equation of line

Therefore the Equation of line is

$y=2x -3$

8 0

3 years ago

The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc

BaLLatris [955]

Answer:

$y(t)= 6-3cos(\dfrac{2\pi}{14}t )$

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

$y(t) = y_0+Acos(wt)$

The tide varies between 3ft and 9ft, which means its amplitude $A$ is

$A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}$

and its midline $y_0$ is

$y_o=3+3 \\\\\boxed{y_o= 6ft}$ .

Furthermore, since at $t=0$ the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is $-cos(\omega t)$ .

The period of the full cycle is 14 hours, which means

$\omega t =2\pi$

$\omega (t+14)= 4\pi$

giving us

$\boxed{\omega = \dfrac{2\pi}{14}.}$

With all of the values of the variables in place, the function modeling the situation now becomes

$\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}$

8 0

3 years ago

What is the slope of the line? y + 5=2(x+1)

mel-nik [20]

Answer:

Step-by-step explanation:

So we have the equation:

$y+5=2(x+1)$

This is in the format point-slope form, where:

$y-y_1=m(x-x_1)$

Here, m is the slope.

In our original equation, 2 replaces m.

Therefore, our slope is 2.

5 0

3 years ago

Read 2 more answers

1/2 of a bag of candy is skittles, 1/4 is m and m's, and 3/4 of the rest of it are life savers. The rest are sour patch kids. Wh

m_a_m_a [10]

Answer:

6.25%

Step-by-step explanation:

Total = 1 ; as a decimal

1/2 = skittles

1/4 = M&Ms

Skittles +M&Ms = 1/2 + 1/4 = 3/4

Remainder = 1 - $\frac{3}{4}$

Remainder = $\frac{1}{4}$

Sour patch = $\frac{1}{4} *\frac{1}{4} =\frac{1}{16}$

As a percentage , multiply 1/16 by 100 and it becomes 6.25%

5 0

3 years ago